promotion image of download ymail app
Promoted

physic problems ?

1. 3. A 0.200 kg air-track glider moving at 1.20 m/s bumps into a 0.600 kg glider at rest.

a.) Find the total kinetic energy after collision if the collision is elastic.

b.) Find the total kinetic energy after collision if the collision is completely inelastic.

Show all your work.

2. 4. An archer pulls a bowstring back 0.440 m, and the spring constant of the bow is 545 N/m.

a.) Find the amount of work the archer did to draw the bow.

b.) Find the speed an arrow of mass 0.060 kg will have when it is shot from the bow.

Assume no losses from friction.

Update:

Physics problems**

2 Answers

Relevance
  • NCS
    Lv 7
    1 month ago
    Favourite answer

    1a) If the collision is elastic, the total KE after the collision is equal to the total KE before the collision, which is

    KE = ½ * 0.200kg * (1.20m/s)² = 0.144 J

    b) If inelastic, then we need to first conserve momentum to find the final velocity:

    0.200kg * 1.20m/s = (0.200+0.600)kg * V

    V = 0.30 m/s

    so

    final KE = ½ * 0.800kg * (0.30m/s)² = 0.036 J

    2a) For a Hookean spring,

    work = ½kx² = ½ * 545N/m * (0.440m)² = 52.8 J

    b) KE = 52.8 J = ½ * 0.060kg * v²

    and so

    v = 41.9 m/s

    If you find this helpful, please select Favorite Answer!

    Source(s): Please revisit this working: https://answers.yahoo.com/question/index?qid=20200...
  • Knr
    Lv 4
    1 month ago

    a) total kinetic energy after collision = 1/2 x0.2x1.2x1.2 = 0.144 J.

    b) for inelastic collision , after collision V = 0.2x1.2 / 0.8 = 0.3 m/sec

    hence kinetic energy after collision is 1/2 x0.8x0.09 = 0.036 J.

    4). (a) work done = 1/2 x 545 x.0.44x0.44 = 52.756J.

    b) speed of arrow v= sq.root(2W/m) = sq.root( 2x52.756/0.06) = 12 m/ sec.

    • Commenter avatarLog in to reply to the answers
Still have questions? Get answers by asking now.