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a car starting from rest accelerates uniformly at 6.1 m/s² for 7.0 sec. how far does the car move?

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  • Knr
    Lv 4
    1 month ago

    distance travelled S = 0+ 1/2x a t’2

    ie., S = 1/2x6.1x49 = 149.45 m.

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  • 1 month ago

    d = Vi*t + ½*a*t² = = 0*7 + ½*6.1*7² = 149.45m

    or about 150 meters

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  • NCS
    Lv 7
    1 month ago

    Welcome to Yahoo!Answers.

    Use the basic kinematic equation

    s = ½at²

    s = ½ * 6.1m/s² * (7.0s)² = 150 m

    to two significant digits, all the data warrants.

    If you find this helpful, please select Favorite Answer. You get points too!

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  • oubaas
    Lv 7
    1 month ago

    distance d = a/2*t^2 = 3.05*7^2 = 149.5 m

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