# a car starting from rest accelerates uniformly at 6.1 m/s² for 7.0 sec. how far does the car move?

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- KnrLv 41 month ago
distance travelled S = 0+ 1/2x a t’2

ie., S = 1/2x6.1x49 = 149.45 m.

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- oldschoolLv 71 month ago
d = Vi*t + ½*a*t² = = 0*7 + ½*6.1*7² = 149.45m

or about 150 meters

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- NCSLv 71 month ago
Welcome to Yahoo!Answers.

Use the basic kinematic equation

s = ½at²

s = ½ * 6.1m/s² * (7.0s)² = 150 m

to two significant digits, all the data warrants.

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