# math question?

The cost of a ticket to the circus is $18.00 for children and $33.00 for adults. On a certain day, attendance at the circus was 1,100 and the total gate revenue was $30,300. How many children and how many adults bought tickets?

The number of children was (

) and the number of adult was (

)

### 8 Answers

- ranjankarLv 71 month ago
LET THE NO OF ADULTS BE X

THEN NO OF CHILDREN = 1100 - X

AMOUNT COLLECTED = 33X + 18( 1100 - X) = 30300

33X + 19800 - 18X = 30300

15X = 10500

X = 700 ADULTS + 400 CHILDREN ANSWER

CHECK

700*33= 23100

400*18 = 7200

ADD = 30300

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- PhilomelLv 73 months ago
18*C+33*A =$30300

C+A =1100

divide by 100

18c+33a=303

use excel

c.........a..........#........$

2.........9..........11.......333

3.........8..........11.......318

4.........7..........11.......303

400C+700A=1100 ppl& $30300

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- PuzzlingLv 73 months ago
Here's an intuitive way to solve this.

Let's say all 1,100 tickets were sold to children. If so, the circus would have made 1,100 * $18 = $19,800

But they actually made $10,500 more than that:

$30,300 - 19,800 = 10,500

For each ticket that is sold to an adult rather than a child, the circus makes an additional $15.

$33 - 18 = 15

Dividing we see the circus sold 700 adult tickets

10,500 / 15 = 700

The other 400 are child tickets.

Answer:

700 adult tickets @ $33 = 23,100

400 child tickets @ 18 = 7,200

---------- . . . . . . . . . . . . . . . -------------

1100 tickets . . . . . . . . . . $30,300

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- PinkgreenLv 73 months ago
Let C=the number of children; A=the number of adults.

C+A=1100

18C+33A=30300

=>

18C+33(1100-C)=30300

=>

15C=6000

=>

C=400

A=1100-400=700

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- sepiaLv 73 months ago
The cost of a ticket to the circus is $18.00 for children and $33.00 for adults.

On a certain day, attendance at the circus was 1,100

and the total gate revenue was $30,300.

How many children and how many adults bought tickets?

x + y = 1100

33x + 18y = 30300

18x + 18y = 19800

15x = 10500

x = 700

y = 400

The number of children was (400)

and the number of adults was (700).

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- JeremyLv 63 months ago
c = number of children; a = number of adults.

System:

{c + a = 1,100 <=== Attendance on a certain day.

{18c + 33a = 30,300 <=== Total revenue on the same day ($).

{c = 1,100 - a.

{18c + 33a = 30,300 ==> Recall "c = 1,100 - a" ==> 18(1,100 - a) + 33a = 30,300 ==>

==> 19,800 - 18a + 33a = 30,300 ==> 19,800 + 15a = 30,300 ==>

==> 15a = 30,300 - 19,800 ==> 15a = 10,500 ==> a = 10,500/15 = 700.

Hence: c = 1,100 - 700 = 400.

ANSWERS: The number of children was 400, and the number of adults was 700.

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- PhilipLv 63 months ago
c-ticket costs $18, a-ticket costs $33. Suppose

[c](c-tickets) were sold. Then [1100-c](a-tickets)

were sold. Total sales = $[c](18) +$[1100-c]33 =

$(18c-33c+33000)=$30,300., ie., 33000 -15c =

30300, ie., 15c = 33000-30300 = 2700, ie.,

30c = 5400, 3c = 540, c = 180. Then number

of (children,adults ) was (180,920).

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- la consoleLv 73 months ago
Number of children: c

Number of adults: a

On a certain day, attendance at the circus was 1,100: → a + c = 1100 → c = 1100 - a

…and the total gate revenue was $30,300:

18c + 33a = 30300 → recall: c = 1100 - a

18.(1100 - a) + 33a = 30300

19800 - 18a + 33a = 30300

15a = 30300 - 19800

15a = 10500

a = 10500/15

a = 700

Recall: c = 1100 - a

c = 1100 - 700

c = 400

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