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Anonymous
Anonymous asked in Science & MathematicsPhysics · 1 month ago

Physics help?

Mary is an avid game show fan and one of the contestants on a popular game show. She spins the wheel and after 1.5 revolutions, the wheel comes to rest on a space that has a $1,500.00 prize. If the initial angular speed of the wheel is 3.95 rad/s, find the angle through which the wheel has turned when the angular speed is 1.50 rad/s.

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  • oubaas
    Lv 7
    1 month ago
    Favourite answer

    stopping angle = 1.5 revs = 3PI radians 

    3PI = Wi*t/2

    stopping time t = 6PI/ Wi = PI*6/3.95 = 1.518 PI sec 

    angular acceleration alpha = Wi/t = 3.95*3.95/(6PI) = 0.828 rad/sec^2

    3.95 -1.5 = alpha*t'

    t' = 2.45/0.828 = 2.96 sec 

    slowing angle =   Wi*t'-alpha/2*t'^2 = 8.06 rads

    or

    (3.95^2-1.5^2) = 2*alpha*slowing angle 

    slowing angle = (3.95^2-1.5^2) / (0.828*2) = 8.06 rads 

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  • Anonymous
    1 month ago

    Where is the question?

    • jenny1 month agoReport

      idk but the final answer should be in revolutions 

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