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jupiter orbits the sun once every 4333 days in a circle of radius 7.79*10^10 m. what is jupiters velocity

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  • 4 months ago
    Favourite answer

    D = 2 x pi x r

    D = 2 x 3.141592 x 7.79 x 10^10m

    D = 4.89 x 10^11m

    4.89 x 10^11 m / 4333 = 1.13 x 10^8 m / day 

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    • Hmmm... 2 x 3.141592 x 77,900,000,000 meters = 489,460,033,600 meters 
      489,460,033,600 meters / 4333 = 112,961,005 meters per day, / 24 = 4,706,708 per hour / 3600 = 1307 m/sec = 1.307 km/sec... I think the distance from the sun to Jupiter should be 7.79 x 10^11m. 

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  • Joseph
    Lv 7
    4 months ago

    This is a speed-time-distance problem. Concentrate on key words:  circle and radius and use your head, it won't hurt, I promise.

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  • Clive
    Lv 7
    4 months ago

    Do your own homework.

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  • 4 months ago

    For what the answer you are requiring is

    29, 205 mph

    Pi Radius x time

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