# Help! Thanks in advance?

jupiter orbits the sun once every 4333 days in a circle of radius 7.79*10^10 m. what is jupiters velocity

### 4 Answers

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- 4 months agoFavourite answer
D = 2 x pi x r

D = 2 x 3.141592 x 7.79 x 10^10m

D = 4.89 x 10^11m

4.89 x 10^11 m / 4333 = 1.13 x 10^8 m / day

- JosephLv 74 months ago
This is a speed-time-distance problem. Concentrate on key words: circle and radius and use your head, it won't hurt, I promise.

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- Ronald 7Lv 74 months ago
For what the answer you are requiring is

29, 205 mph

Pi Radius x time

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Hmmm... 2 x 3.141592 x 77,900,000,000 meters = 489,460,033,600 meters

489,460,033,600 meters / 4333 = 112,961,005 meters per day, / 24 = 4,706,708 per hour / 3600 = 1307 m/sec = 1.307 km/sec... I think the distance from the sun to Jupiter should be 7.79 x 10^11m.