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KHP titration?

answer the following questions based on the reaction below: NaOH(aq) + KHP(s) --> NaKP(aq)+H2O(I)

A 1.864 g sample of impure KHP was titrated with a 0.0978 M solution of NaOH. To completely react the KHP in the sample, 72.14 mL of base was needed. KHP (potassium hydrogen phthalate, 204.23 g/mol)

a.) How many grams of KHP were in the unknown sample?

b.) What is the percentage of KHP in the unknown sample?

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  • david
    Lv 7
    1 month ago
    Favourite answer

    NaOH(aq) + KHP(s) --> NaKP(aq)+H2O(I)

    A 1.864 g sample of impure KHP was titrated with a 0.0978 M solution of NaOH. To completely react the KHP in the sample, 72.14 mL of base was needed. KHP (potassium hydrogen phthalate, 204.23 g/mol)

    a.) How many grams of KHP were in the unknown sample?

       0.0978 M X 0.07214L X 204.23 g/mol

       =  1.441 g  <<<  answer

    b.) What is the percentage of KHP in the unknown sample?

       1.441/1.864   X 100  =  77.31%  <<<  anwer

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