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Anonymous asked in Science & MathematicsChemistry · 1 month ago

The following reaction is first order in N2O5: N2O5(g)→NO3(g)+NO2(g) The rate constant for the reaction at a certain temperature is 0.053/s.?

What would the rate of the reaction be at the same concentration as in part a if the reaction were second order? or Zero order?(Assume the same numerical value for the rate constant with the appropriate units.)

Express your answer using two significant figures.

1 Answer

  • 1 month ago

    For a second order reaction, the rate law would be:

    rate = k [N2O5]^2

    rate = 0.053 [N2O5]^2 = _______

    You didn't provide a concentration of N2O5 to use in this calculation.

    For a zero order reaction, the rate law is simply rate = k = 0.053 M/s

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