promotion image of download ymail app

Titration of 30mL of 0.08M acetic acid solution with 0.0850M KOH. What's the analytical concentration of acetate ions at equivalence point?

1 Answer

  • 2 months ago

    Supposing the potassium acetate ionizes completely:

    (30 mL) x (0.08M acetic acid) x (1 mol acetate / 1 mol acetic acid) / (58 mL) =

    0.041 M acetate

    • Commenter avatarLog in to reply to the answers
Still have questions? Get answers by asking now.