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Can you solve this resistor physics question?

What resistance must be placed in parallel with a 184- resistor to make the equivalent resistance 119?

6 Answers

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  • 2 months ago
    Favourite answer

    (184*119)/(184-119)=337Ω

    336Ω .5% resistor  or 340 .5%

    • Andrew Smith
      Lv 7
      2 months agoReport

      Note that a 5% tolerance in the 337 ohm resistor gives 2% variation in the combination. ie 117<R<121 ohm.. If you were to choose from standard values a 330 ohm 5% resistor is the closest that you could obtain from the common 5% range.

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  • oubaas
    Lv 7
    2 months ago

    119 = 184*R / (184+R)

    21896 = R(184-119)

    R = 21896 / (184-119) = 336.9 ohm

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  • Sky
    Lv 7
    2 months ago

    One way to write the parallel resistance formula is (R1 x R2)/(R1+R2)

    So, for the mystery resistance R, write it as (184 x R)/(184+R)=119

    Solve for R.  If you understand algebra, this is easy.

    The usual parallel resistance formula is:

    1

    ------------------------------

    (1/R1)+(1/R2)+(1/R3)...

    So, if you write

    1

    ------------------   = 119  and solve for R, you'll get the same answer.

    (1/184)+(1/R)

    Source(s): I once tutored algebra
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  • 2 months ago

    I can also

    .................

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  • Anonymous
    2 months ago

    Yes I can                    

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  • 2 months ago

    An electric turbocharger.

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