How do you solve these equations?

S1= $81,000 + [0.2 × ($16,000 +0.7 × S1)]

solve for S1

3 Answers

Relevance
  • 4 weeks ago

    S1 = $81,000 + [0.2 × ($16,000 + 0.7 × S1)]

    S1 = $81,000 + [($3,200 + 1.4 S1)]

    1.4 S1 - S1 =  $84,200

    S1 

    • Log in to reply to the answers
  • 4 weeks ago

    S1= $81,000 + [0.2 × ($16,000 +0.7 × S1)]

    S1 = 81,000 + 0.2(16,000 + 0.7S1)

    S1 = 81,000 + 3200 + 0.14S1

    S1 = 84,200 + 0.14S1

    S1 - 0.14S1= 84,200

     0.86S1 = 84,200

     S1 = 97906.97 or $ 97907 answer//

    • Log in to reply to the answers
  • 4 weeks ago

    S1= $81,000 + [0.2 × ($16,000 +0.7 × S1)]

    S1= $81,000 + [0.2($16,000 + 0.7S1)]

    S1= $81,000 + [$3200 + 0.14S1]

    S1= $81,000 + $3200 + 0.14S1

    S1 – 0.14S1 = $84200

    0.86S1 = $84200

    S1 = $84200 / 0.86

    S1 = $97906.98

    check

    $97906.98 = $81,000 + [0.2 × ($16,000 + 0.7 × $97906.98)]

    $97906.98 = $81,000 + [0.2 × ($16,000 + $68534.88)]

    $97906.98 = $81,000 + [0.2 × ($84534.88)]

    $97906.98 = $81,000 + [$16906.98]

    $97906.98 = $97906.98

    ok

    • ...Show all comments
    • billrussell42
      Lv 7
      4 weeks agoReport

      no, that number is still rounded off. 

      to a bit more accuracy: 97906.9767441860
      it does eventually repeat, but the repeat cycle is quite long
      https://www.mathsisfun.com/calculator-precision.html

    • Log in to reply to the answers
Still have questions? Get answers by asking now.