magnitude of flux due to electric force?
A charge Q exerts a 12 N force on another charge q. If the distance between the charges is doubled, what is the magnitude of the electric force exerted on Q by q?
- Anonymous8 months agoFavourite answer
F' = F*d^2 / (2d)^2 = F/4 = 3 N
- billrussell42Lv 78 months ago
double the distance, the force is 1/4 (inverse square law)
12/4 = 3 N