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Anonymous
Anonymous asked in Science & MathematicsMathematics · 2 months ago

Write the functions on parameter form?

a) (x^2)/4 + (y^2)/9 = 1

b) 4(x^2) + 9(y^2) = 36

c) (x-1)^2 + (y+2)^2 = 9

1 Answer

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  • 2 months ago

    Remember sin²(t) + cos²(t) = 1.

    ________

    a)

    x²/4 + y²/9 = 1

    (x/2)² + (y/3)² = 1

    Since sin²(t) + cos²(t) = 1

    Let sin(t) = x/2

    Let cos(t) = y/3

    x = 2sin(t) a nd y = 3cos(t)

    ________

    b)

    4x² + 9y² = 36

    We want '1' on the right hand side so divide equation by 36.

    x²/9 + y²/4 = 1

    then use the same method as for a).

    ________

    c)

    (x-1)² + (y+2)² = 9

    ((x-1)/3)² + ((y+2)/3)² = 1

    sin(t) = (x-1)/3

    x = 2sin(t) + 1

    You can find the equation for y the same way

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