Anonymous
Anonymous asked in Science & MathematicsMathematics · 8 months ago

How tall is a 4 foot block - angled at 45 degrees?

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  • Lôn
    Lv 7
    8 months ago
    Favourite answer

    If you mean the block is leaning against a wall at 45 degrees.

    Let height (and dist of base from wall) = x

    Then by Pythagoras' theorem x^2 + x^2 = 4^2

    2x^2 = 16

    x^2 = 8

    x = root 8 = 2.83 feet.

  • cosmo
    Lv 7
    8 months ago

    What do you mean by a 4 foot block? 

    A 4 x 4 square, standing on edge, is 4 * squareroot(2) =5.66

    A 4 ft high thing, leaning over by 45 degrees is

    4 / squareroot(2) = 0.707

  • Anonymous
    8 months ago

    A little under 6 feet.

  • 8 months ago

    hmm how about 4 feet

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  • KennyB
    Lv 7
    8 months ago

    4 foot divided by the square root of two - approx 1.4 - so the height will be 2.85 foot.

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