How tall is a 4 foot block - angled at 45 degrees?
- LônLv 71 month agoFavorite Answer
If you mean the block is leaning against a wall at 45 degrees.
Let height (and dist of base from wall) = x
Then by Pythagoras' theorem x^2 + x^2 = 4^2
2x^2 = 16
x^2 = 8
x = root 8 = 2.83 feet.
- cosmoLv 71 month ago
What do you mean by a 4 foot block?
A 4 x 4 square, standing on edge, is 4 * squareroot(2) =5.66
A 4 ft high thing, leaning over by 45 degrees is
4 / squareroot(2) = 0.707
- Anonymous1 month ago
A little under 6 feet.
- 1 month ago
hmm how about 4 feet
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- KennyBLv 71 month ago
4 foot divided by the square root of two - approx 1.4 - so the height will be 2.85 foot.