Anonymous

# How tall is a 4 foot block - angled at 45 degrees?

title

### 5 Answers

Relevance

- LônLv 71 month agoFavorite Answer
If you mean the block is leaning against a wall at 45 degrees.

Let height (and dist of base from wall) = x

Then by Pythagoras' theorem x^2 + x^2 = 4^2

2x^2 = 16

x^2 = 8

x = root 8 = 2.83 feet.

- Log in to reply to the answers

- cosmoLv 71 month ago
What do you mean by a 4 foot block?

A 4 x 4 square, standing on edge, is 4 * squareroot(2) =5.66

A 4 ft high thing, leaning over by 45 degrees is

4 / squareroot(2) = 0.707

- Log in to reply to the answers

- Anonymous1 month ago
A little under 6 feet.

- Log in to reply to the answers

- What do you think of the answers? You can sign in to give your opinion on the answer.
- KennyBLv 71 month ago
4 foot divided by the square root of two - approx 1.4 - so the height will be 2.85 foot.

- Log in to reply to the answers

Still have questions? Get answers by asking now.