How far away do I have to be from Los Angeles after a nuclear bomb is dropped on it ?
- 2 weeks ago
Go to new York. It's better to be safe than sorry.
- 3 weeks ago
If its the size of the tsar bomb you would need to be over 100 miles away
- Anonymous4 weeks ago
Texas is a good start.
- Andrew SmithLv 74 weeks ago
The biggest long term threat is the radioactive dusts raised into the atmosphere by the bomb. These are carried by wind giving a risk of lethal radiation damage and an increased risk of long term cancers. The risk area depends on the winds. As you day AFTER a bomb is dropped I am guessing you mean fall out damage.
OK imagine a bomb was dropped on LA is that likely to be the ONLY bomb dropped. Most scenarios show that the entire world would become uninhabitable after a nuclear exchange. People in Australia would last the longest but the "nuclear winter" would guarantee no food, no crops, no rain. There could be no winners given the scale of the arsenal that is now held.
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- 4 weeks ago
Los Angeles would actually become much more habitable after a nuclear blast. And property would be affordable.
- SpacemanLv 74 weeks ago
Check out the simulator NUKEMAP cited below. You have numerous options in adjusting the various parameters.
Effect distances for a 5 megaton airburst*: ▼
Fireball radius: 1.84 km (10.6 km²)
Maximum size of the nuclear fireball; relevance to damage on the ground depends on the height of detonation. If it touches the ground, the amount of radioactive fallout is significantly increased. Anything inside the fireball is effectively vaporized. Minimum burst height for negligible fallout: 1.66 km.
Moderate blast damage radius (5 psi): 12 km (454 km²)
At 5 psi overpressure, most residential buildings collapse, injuries are universal, fatalities are widespread. The chances of a fire starting in commercial and residential damage are high, and buildings so damaged are at high risk of spreading fire. Often used as a benchmark for moderate damage in cities. Optimal height of burst to maximize this effect is 5.34 km.
Thermal radiation radius (3rd degree burns): 24.5 km (1,880 km²)
Third degree burns extend throughout the layers of skin, and are often painless because they destroy the pain nerves. They can cause severe scarring or disablement, and can require amputation. 100% probability for 3rd degree burns at this yield is 12.4 cal/cm2.
Light blast damage radius (1 psi): 33.8 km (3,590 km²)
At a around 1 psi overpressure, glass windows can be expected to break. This can cause many injuries in a surrounding population who comes to a window after seeing the flash of a nuclear explosion (which travels faster than the pressure wave). Often used as a benchmark for light damage in cities. Optimal height of burst to maximize this effect is 7.99 km.
*Detonation altitude: 5,340 m. (Chosen to maximize the 5 psi range.)Source(s): https://nuclearsecrecy.com/nukemap/
- MurzyLv 71 month ago
The fall-out would drift all across the US.
- RealProLv 71 month ago
Depends on where it's dropped. If it's downtown you want to be in the downtown.
- Anonymous1 month ago
In the world and of the world, those involved in that business reap the nature of it asleep in anamnesis.
This is because those who lead into captivity are taken.
Thus live in Callinfawnear twinned LossAngeles.
- Anonymous1 month ago
Phoenix... 15 chars.