Anonymous
Anonymous asked in Science & MathematicsPhysics · 1 month ago

calc help?

A particle is moving with acceleration a(t)= 6t +16. Its position at time t =0 is s(0) =8 and its velocity at time t =0 is v(0)= 17. What is its position at time t = 14? 

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  • NCS
    Lv 7
    1 month ago

    v(t) = ∫ a(t) dt = ∫ (6t + 16) dt = 3t² + 16t + C

    and we're told

    v(0) = 17 = 3*0² + 16*0 + C

    and so

    C = 17

    s(t) = ∫ v(t) dt = ∫ (3t² + 16t + 17) dt = t³ + 8t² + 17t + D

    and we're told

    s(0) = 8 = 0³ + 8*0² + 17*0 + D

    and so

    D = 8

    and

    s(t) = t³ + 8t² + 17t + 8

    then

    s(14) = 4558

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  • Vaman
    Lv 7
    1 month ago

    Equation is wrong. Velocity from the equation is 6 not 17. You will not get the answer.

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