What is the distance from the mass to the circle?
A block of mass 0.5 kg is pushed against a horizontal spring of negligible mass, compressing
the spring a distance of ∆x as shown in the figure. The spring constant is 467 N/m. When
released, the block travels along a frictionless,
horizontal surface to point B, the bottom of
a vertical circular track of radius 0.7 m, and
continues to move up the track. The speed
of the block at the bottom of the track is
16 m/s, and the block experiences an average frictional force of 6 N while sliding up the
The acceleration of gravity is 9.8 m/s 2.
What is ∆x?
Answer in units of m.
Please give an explanation!
What is the speed of the block at the top of
- NCSLv 78 months agoFavourite answer
Most of the data is irrelevant as far as the question goes.
Spring energy becomes kinetic energy:
½kx² = ½mv²
467N/m * x² = 0.5kg * (16m/s)²
x = 0.52 m