# 0.025 kg bullet is fired from a gun with a velocity of -230 m/s. If the gun has a mass of 0.52kg, what is the recoil velocity of the gun? ?

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- MyRankLv 69 months ago
Given,

Mass of bullet (mb) = 0.025kg

Velocity of bullet (vb) = 230m/sec

Mass of Gun (mg) = 0.52kg

Velocity of Gun (vg) = ?

Using conservation of momentum:-

m_b v_b = mgvg

→ vg = m_b v_b/m_g = 0.025kg x 230m/sec / 0.52kg = 5.75/0.52 = 11.05m/sec

∴ velocity of Gun (vg) = 11.05m/sec.

Source(s): https://myrank.co.in/ - Anonymous10 months ago
Vrg = -Vb*mb/mg = 230*0.025/0.52 = 11.06 m/sec

- Anonymous10 months ago
Conservation of momentum, your teacher will have gone over this. google that on Youtube.

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- USAFisnumber1Lv 710 months ago
Mass of bullet x speed of bullet = mass of gun x speed of gun. Start plugging in numbers and do the math.

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