# electric circuit question?

I do not have any idea to solve this question. Can you solve this?

### 1 Answer

Relevance

- oldschoolLv 72 months ago
ω = 4000 rad/s

Find impedances:

-j/(4000*20e-6) = -j12.5 for capacitor.

j*4000*15e-3 = j60 for the inductor

v(t) = [0.120*(-j12.5)/(40 - j12.5 + j60)]*40Ω

v(t) = [0.120*(-j12.5)/(40 + j47.5)]*40Ω

Convert to polar form

[0.12*(12.5/_-90°)/(62.1/_49.9°)]*40Ω

v(t) = 0.966 /_-139.9° <<<<<

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