- 3 weeks ago
use a calculator
- JOHNLv 73 weeks ago
EDIT: For the benefit of the unenlightened one who saw fit to give this answer a TD.
The identity (10p + q)(10r + s) = 100pr + 10(ps + qr) + qs (0 ≤ p, q, r, s ≤ 9) is the basis of the scribblings below. The way the method works in practice is as follows. Take 89 x 67. Multiply last two digits; you get a 3 for the last digit of the answer with a 6 to be carried forward to the tens; take the cross products and add; you get 8 x 7 + 9 x 6 = 110; taking into account the c/f 6, we get 6 in the tens space with an 11 c/f; finally multiply the two 1st digits; with the 11 c/f we get 59 (8 x 6 + 11). Answer 5963. The method works for any 2-digit numbers. You don't have to know the rationale for the method to apply it - you can do so by rote. I had assumed that the people on this forum are sophisticated enough to work out for themselves the mathematical basis of what I did. I reckon you can train a chimpanzee to so sums of this sort, since one doesn't really need to go into the justification.
3 x 3 = 9 units
3 x 7 + 8 x 3 = 45 = 5 tens and 4 hundreds
8 x 7 = 56 hundreds
Add the 4 hundreds = 60 hundreds
Answer = 6059
(All of you should be able to do the first four steps in your heads and write the answer down in one go; my 3-year old granddaughter can do it).
- DavidLv 73 weeks ago
The product of 83 and 73 is 6059
- SumDudeLv 73 weeks ago
grab a clean piece of paper and a sharp pencil and do what you learned in 4th grad.Source(s): No math skills means no high paying job.
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- PhilipLv 63 weeks ago
83*73 = 83(83-10) = (80+3)^2 -830 = 6409+480-830 = 6889 -830 = 6059.Source(s): Self
- sepiaLv 73 weeks ago
83 multiplied by 73 equals 5810 + 249 = 6059
- 3 weeks ago
Use a calculator
- Anonymous3 weeks ago
Skippy's calculator broken?
- JayLv 63 weeks ago
Something that can be very easily figured out by using a calculator