# Physics Ut Quest Help?

A ball is thrown horizontally from the top of a building 14.8 m high. The ball strikes the ground at a point 72.5 m from the base of the building.

Find the y component of its velocity just before it strikes the ground.Answer in units of m/s.

### 1 Answer

Relevance

- billrussell42Lv 79 months ago
vertical velocity is the same as if you dropped it.

v = √(2gh) = √(2•9.8•14.8) = 17.0 m/s

falling object starting from rest

h is height in meters, t is time falling in seconds,

g is acceleration of gravity, usually 9.8 m/s²

v is velocity in m/s

h = ½gt²

t = √(2h/g)

v = √(2gh)

h = v²/2g

v = gt

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