5.60 m length of 1.8 mm -diameter wire carries a 770 mA current when 18.0 mV is applied to its ends. The drift velocity is 1.3×10−5 m/s?

Find resistance of the wire

Update:

Determine the electric field inside the wire and number of free electrons per unit volume 

3 Answers

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  • MyRank
    Lv 6
    4 weeks ago
    Best answer

    Given,

    Current (I) = 770mn = 770 x 10⁻³A

    Voltage (v) = 18mv = 18 x 10⁻³volts

    Resistance (R) = ?

    Diameter of wire (D) = 1.8 x 10⁻³m

    Length of wire (L) = 5.60m

    We know that:-

    Voltage (v) = current (I) x resistance (R)

    Resistance (R) = voltage (v) / current (I) = 18 x 10⁻³ / 770 x 10⁻³

    = 0.023Ω

    ∴ Resistance (R) = 0.023Ω.

  • 4 weeks ago

    R=E/I >>R=18/770 = .023377Ω

  • NCS
    Lv 7
    4 weeks ago

    resistance = potential / current

    R = 18.0mV / 770mA = 0.0234 Ω

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