Anonymous
Anonymous asked in Education & ReferenceHomework Help · 1 month ago

I need help with algebra yes I have tried to figure it out ?

Penny made a 74% on her first test.What must she get on her next test to have an average of at least 80%  (100 points per test)?

Update:

Write an equation

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  • 1 month ago
    Favorite Answer

    (0.74+x)/2 = 0.8

    The average is equal to the sum of the values divided by the number of things you added... so 74% (or 0.74 as a decimal) plus x (what her next test percentage should be, as a decimal) equals her desired test average, or 80% (0.8). 

    When you solve this equation, you get 0.86, or 86%. Thus, she must get at least an 86 on her next test...hope this helped

    Source(s): high school experience lol
    • SumDude
      Lv 7
      1 month agoReport

      {You are correct, but ...}  geez ... 80 + 80 - 74 = 86 ... for this simple problem.

  • Joe
    Lv 5
    1 month ago

    Try to figure it out.

  • David
    Lv 7
    1 month ago

    Let x be percentage of next test and so if (74+x)/2 = 80 then x = 86%

  • VP
    Lv 7
    1 month ago

    You could also have done it using a bit of logic.

    1. You know that each test is based on 100%.

    2. You know Penny got a 74 on the 1st test.

    3. You know that 74 is 6 less than 80. 

    That would mean she'd have to score 6 MORE than 80 on the next test, which is an 86.  That would balance things out.  She was 6 less than 80 on the 1st test; she needs to be 6 over 80 on the 2nd test.

    Equation: (x + y) / 2 = 80; x = 74; Solve for y

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  • 1 month ago

    86%.... lucky guess

  • 1 month ago

    2 tests, max 200 points

    80% of 200 = 160

    so she needs 160 - 74 = 86 points on her second test

    • jxmes1 month agoReport

      What could I put for an equation I forgot to mention I needed one 

  • Anonymous
    1 month ago

    42

    It’s always 42

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