Anonymous
Anonymous asked in Science & MathematicsEngineering · 4 weeks ago

If the pressure loss is 42.8 lb/sq. in, what’s the flow rate?

The pressure loss F (in pounds per square inch) of a hose is given by F=2Q^2+Q where Q is the flow rate (in hundreds of gallons per minute) of water through the hose. 

2 Answers

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  • 4 weeks ago

    2Q^2 + Q -42.8 =0

    a=2 b=1 c=-42.8

    Q= (-b +/- sqrt(b^2-4ac)

    Its the quadratic formula you learned in high school algebra,not rocket science

  • 4 weeks ago

    F = 2Q² + Q = 42.8

    2Q² + Q – 42.8 = 0

    using a quadratic solver

    Q = 4.37 (100s gal/min) or 437 gal/min

    long way:

    quadratic equation:

    to solve ax² + bx + c = 0

    x = [–b ± √(b²–4ac)] / 2a

    Q = [–1 ± √(1+8•42.8)] / 4

    Q = [–1 ± 18.477} / 4

    Q = 4.37

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