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# If the pressure loss is 42.8 lb/sq. in, what’s the flow rate?

The pressure loss F (in pounds per square inch) of a hose is given by F=2Q^2+Q where Q is the flow rate (in hundreds of gallons per minute) of water through the hose.

### 2 Answers

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- 4 weeks ago
2Q^2 + Q -42.8 =0

a=2 b=1 c=-42.8

Q= (-b +/- sqrt(b^2-4ac)

Its the quadratic formula you learned in high school algebra,not rocket science

- billrussell42Lv 74 weeks ago
F = 2Q² + Q = 42.8

2Q² + Q – 42.8 = 0

using a quadratic solver

Q = 4.37 (100s gal/min) or 437 gal/min

long way:

quadratic equation:

to solve ax² + bx + c = 0

x = [–b ± √(b²–4ac)] / 2a

Q = [–1 ± √(1+8•42.8)] / 4

Q = [–1 ± 18.477} / 4

Q = 4.37

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