# Math for business question?

A basketball team sells tickets that cost $10, $20, or, for VIP seats, $30. The team has sold 3237 tickets overall. It has sold 183 more $20 tickets than $10 tickets. The total sales are $60,750. How many tickets of each kind have been sold?

How many $10 tickets?

How many $20 tickets?

How many $30 tickets?

### 3 Answers

- L. E. GantLv 710 months ago
x = # $10 tickets

y = # $20 tickets

z = # $30 tickets

x + y + z = 3237

y - x = 183 or x = y - 183

so 2y + z = 3420 ...... add these two equations together

10*x + 20*y + 30*z = 60750 .......... the dollar amounts

==> 10(y - 183) +20y + 30z = 60750

==> 30y + 30z = 60750 + 1830

==> y + z = 2025 + 61

==> y + z = 2086

==> y = 3420 - 2086 = 1334

hence z = 2086 -1334 = 752

and x = 1334 - 183 = 1151

so 1151 $10 tickets

and 1334 $20 tickets

and 752 $30 tickets

total 3237 tickets.... (check)

- KaleyKLv 710 months ago
$10 x 1,151 = $11,510

$20 x 1,334 = $26,680

$30 x 752 = $22,560

1,151 + 1,334 + 752 = 3,237 tickets sold

$11,510 + $26,680 +$22,560 = $60,750