# Airplane climbs at angle of 11 degrees. Find the ground distance it has travelled with it reaches altitude of 400ft. There is no more info.?

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Let the ground distance be, x.

400/x = tan 11

x = 400/tan11 = 2,057.82 ft

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• -

tan 11° = 400 / x

x = 400 / tan 11°

x = 2058 ft_______ground distance

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• Ground diatance: 400/tangent(11) = 2058 feet to the nearest foot

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• Anonymous
7 months ago

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• Anonymous
7 months ago

You don't need any more information. Tan 11 deg = opposite (400) / adjacent (distance to be found)

400/ tan 11 deg = distance.

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• So you know that the angle is 11° and the side opposite of the angle is 400 ft. You want to find the length of the adjacent side. So use the tangent law.

tan 11° = 400/x

x = 400/(tan 11°)

x = 2058 ft

When it’s a right triangle, know these three acronyms:

CAH - cos x = adjacent/hypotenuse

SOH - sin x = opposite/hypotenuse

TOA - tan x = opposite/adjacent

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• d = 400/tan11 = 400/0.194380309 = 2057.82161 feet

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