A group of six acrobats finishes its act in a triangular formation as shown.?
Find the number of different ways that the group can finish in this way, if the lightest acrobat must be at the top and the two strongest acrobats must have their feet on the ground
- PuzzlingLv 78 months ago
You have 1 choice for where the lightest acrobat goes.
The strongest acrobat would have a choice of 3 positions on the bottom.
The second strongest acrobat would have a choice 2 remaining positions on the bottom.
Then you can arrange the remaining 3 acrobats into any of the 3 remaining positions --> 3! = 6 ways
1 * 3 * 2 * 3!
= 6 * 6
= 36 ways