# Calculus help?

The line y= Ax+B is tangent to the graph of f(x)=x^2 at the point P=(-4,16). Find A and B.

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- billrussell42Lv 79 months agoFavourite answer
The line y= Ax+B is tangent to the graph of f(x)=x² at the point P=(-4,16). Find A and B.

slope of the curve is f' = 2x

at x = –4, slope is 2(–4) = –8

therefore straight line is

y = (–8)x + B

find b by plugging in point

16 = (–8)(–4) + B16 = 32 + BB = 16 – 32 = – 16equation of line isy = –8x – 16

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