48% NaOH amount 2liter:
(48g Sodium hydroxide + 52g Water)
Plan to use Sodium Hydroxide (M.Wt 40,00 g/mol)
Pellets type How many grams i need to get 2liter as Current recipe?
This is not a well written question:
By itself: 48% NaOH is meaningless unless you specify whether you mean 48%m/m or 48%m/v
But seeing that you later specify 48g NaOH + 52g H2O - the solution must be 48%m/m
Then it is difficult , based solely on the information given , to work out how to make 2L of this solution . You do not know the volume of 48g NaOH dissolved in 52g water
From other data I have determined that a 48%m/m solution of NaOH has density = 1.510g/cm³
If you wish to produce 2.0L of such a solution , this will have mass :
Mass = 2.0L * 1000cm³ /L * 1.510g/cm³ = 3,020g solution
Mass of NaOH required = 48/100*3020 = 1,449.6g NaOH
Weigh out 1,449.6g NaOH and slowly add to approx .0L water . A large amount of heat will be generated . Slowly add the NaOH - allowing solution to cool between additions. When all the NaOH has been added , finally add sufficient water to have a final volume = 2.0L
You do not make the calculation: weigh out XXX g of NaOH and dilute in YYY g or cm³ of water. The "molecular weigh" or more correctly molar mass NaOH = 40g/mol is not required for this problem.