# find the values of the trigonometric functions of θ from the information given cos(θ) = 3/19 , sin(θ) < 0?

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- DWReadLv 79 months ago
cosθ = 3/19

secθ = 1/cosθ = 19/3

sin²θ = 1-cos²θ = 352/19²

√(352/19²) = 4√22/19

sinθ = -4√22/19

cscθ = 1/sinθ = -19/(4√22) = -19√22/88

tanθ = sinθ/cosθ = -4√22/3

cotθ = 1/tanθ = -3/(4√22) = -3√22/88

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- Geeganage WLv 59 months ago
cos(θ) = 3/19; θ = 2nπ±cos^-1(3/19), where n is an integer.

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