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find the values of the trigonometric functions of θ from the information given cos(θ) = 3/19 , sin(θ) < 0?

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  • DWRead
    Lv 7
    9 months ago

    cosθ = 3/19

    secθ = 1/cosθ = 19/3

    sin²θ = 1-cos²θ = 352/19²

    √(352/19²) = 4√22/19

    sinθ = -4√22/19

    cscθ = 1/sinθ = -19/(4√22) = -19√22/88

    tanθ = sinθ/cosθ = -4√22/3

    cotθ = 1/tanθ = -3/(4√22) = -3√22/88

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  • 9 months ago

    cos(θ) = 3/19; θ = 2nπ±cos^-1(3/19), where n is an integer.

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  • alex
    Lv 7
    9 months ago

    Rule

    sin^2(x)+cos^2(x)=1

    tan(x)=sin(x)/cos(x)

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  • 9 months ago

    I'll give you some tips,

    x, y, r

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