Anonymous
Anonymous asked in Science & MathematicsPhysics · 6 months ago

Consider a brick of dimensions, length = 8.0 in (in = inch), width = 4.0 in, and thickness = 3.0 in.?

Consider a brick of dimensions, length = 8.0 in (in = inch), width = 4.0 in, and thickness = 3.0 in. What’s the maximum number of bricks that can be stored, one layer thick, on a floor of width = 8.0 ft and length = 16.0 ft.?

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  • 6 months ago

    I used to have to do this sort of thing when in grade 5 and 6 almost 60 years ago.

    It was SO much better if the bricks were 8 3/16 " and 4 1/8 " Much more fun.

    However the maximum number of bricks will be when they are stood on their ends.

    ie the part touching the floor is 4 " * 3"

    turn that into feet 1/3 * 1/4 = 1/12 ft ^2

    ie you can fit 12 bricks into a single square foot.

    The area of the floor is 8 * 16 = 128 ft^2

    so the number of bricks is bricks/sq ft * area in sq ft

    = 12 * 128 = 1536 bricks

    Note that stacked in other orientations we would get a smaller number of bricks.

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