If y varies directly as x and inversely as the square of z, and y=8 when x=4 and z=3, find y when x=6 and z=-2?

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  • Como
    Lv 7
    6 months ago

    -

    y = k x / z²

    k = y z² / x = 8 x 9 / 4 = 18

    y = 18 x 6 / 4

    y = 27

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  • TomV
    Lv 7
    6 months ago

    y = kx/z²

    8 = k(4/9) → k = 72/4 = 18

    y = 18x/z²

    y = 18(6/4) = 27

    ans: 27

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  • 6 months ago

    y = k(x/z²)

    8 = k(4/3²)

    8 = k(4/9)

    k = 18

    y = k(x/z²)

    y = 18[6/(-2)²]

    y = 18(6/4)

    y = 27

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