A soccer player can kick the ball 29 m on level ground, with its initial velocity at 42 ∘ to the horizontal.?

1 Answer

Relevance
  • NCS
    Lv 7
    6 months ago

    You haven't completed your question. You can use the Update feature to do that. But based on the data you've supplied, we can find the launch velocity using

    range x = V²sin(2Θ)/g

    29 m = V² * sin84º / 9.8m/s²

    solves to

    V = 16.9 m/s

    Now you can find other things, like

    a/ time of flight t = 2·V·sinΘ/g

    b/ max. height h = (V·sinΘ)² / (2g)

    c/ max range this player can kick the ball (assuming the launch speed is constant):

    X = V² / g

    If you find this helpful, please award Best Answer. You get points too!

    • Log in to reply to the answers
Still have questions? Get answers by asking now.