Mathematics?

Sam invested $2150, part of it at 6 percent and the rest at 8 percent yearly interest. The yearly income on the 8 percent investment was $22 more than twice the income from the 6 percent investment. How much did he invest at each rate?

investment at 6 percent

investment at 8 percent

3 Answers

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  • alex
    Lv 7
    5 months ago

    Hint:

    Let x be the part at 6%

    then the part at 8% is (2150 - x)

    set up an equation then solve for x

  • Mike G
    Lv 7
    5 months ago

    Let x be the amount invested at 6%

    Interest accrued at 6% = 0.06*x

    Interest accrued at 8% = 0.08*(2150-x)

    0.08*(2150-x) = 0.12x+22

    150 = 0.2x

    x = 750

    $750 at 6%

    $1400 at 8%

  • 5 months ago

    Let x be the part at 6%

    then the part at 8% is 2150 - x

    so 0.08* (2150 -x) = 22 + 2*0.6*x

    ==> 2150 * 8/100 - 8x/100 = 22 + 12x/100

    ==>2150 * 8 -8x = 2200 +12x

    ==> 15000 = 20x

    ==> x = 750

    So 750 at 6% and (2150-750) = 1400 at 8%

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