A fair coin is tossed 6 times. Compute the probability of tossing 6 heads in a row.?

Relevance
• 6 months ago

A fair coin is tossed 6 times.

Compute the probability of tossing 6 heads in a row.

Probability of getting 6 heads in a row: 1/2^6 = 1/64

• 6 months ago

• 6 months ago

(1/2) (1/2) (1/2) (1/2) (1/2) (1/2) = (1/2)^6

• 6 months ago

p(6 heads in a row) =

(1/2)^6 = 1/64

• Anonymous
6 months ago

1 in 64 is the chance.

• 6 months ago

P = 1/ 2^6 = 1/64

• 6 months ago

Total number of possible outcomes is 2^6 which is 64

There is only one way to get 6 heads.

The probability of tossing 6 heads in a row is 1/64

Things would get more complicated somewhat if less than 6 heads were involved, because permutations and/or combinations would be brought in.

• A.J.
Lv 7
6 months ago

1 in 2, or 50% on each toss to get a head assuming no stand-on-edge or coin down the sewer tosses.

0.5 raised to the 6th power

0.5 x 0.5 x 0.5 x 0.5 x 0.5 x 0.5

or

1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2

1/64 or 0.015625 or 1.5625%

• 6 months ago

One chance in 64.

• 6 months ago

1/2^6.

Toss it once, the odds of heads is 1/2

Toss it twice and the odds of two head is 1/4 (1/2*1/2)

Toss it three times and the odds of three heads is 1/8 (1/2*1/2*1/2)

You can see that the odds of all heads is (1/2)^n where n is the number of coin tosses.

EDIT - It's not 1/2^6, it's (1/2)^6. Sorry about that.