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# What is the amount of heat involved in calories given off when 25 g of water cools from 86oC to 61oC?

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- pisgahchemistLv 71 year ago
heat given off ....

q = -mcΔT = 25g x 1.00 cal/gC x 25C = -625 cal

..... be sure to include the units

..... must be rounded to two significant digits ......... -630 cal

..... the negative sign indicates that the heat is being given off.

- electron1Lv 71 year ago
Heat energy = Mass * Specific heat * ∆ T

The specific heat is 1 cal/(g * T)

Q = 25 * 1 * (86 – 61) = 625 calories

I hope this is helpful for you.

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