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100 − 121k² = 0 What are the solutions to the equation above?

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  • mizoo
    Lv 7
    1 year ago
    Favourite answer

    100 - 121k^2 = 0

    k^2 = 100/121

    k = ± √(100/121)

    k = ± 10/11

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  • 1 year ago

    I don't know, but the one below looks interesting!

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  • 1 year ago

    100-121k^2=0

    100/121=(121k^2)/121

    k^2=100/121

    sqrt(k^2)=sqrt(100/121)

    k=10/11

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    • C
      Lv 5
      1 year agoReport

      The questioner called it an equation, NOT a function. Had the equation been stated to be a function, then, yes, you would be correct that there is only one answer.

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  • Como
    Lv 7
    1 year ago

    :-

    k² = 100 / 121

    k = ± 10/11

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  • 1 year ago

    100 - 121k^2 = 0 can be written as:

    100 = 121k^2. So 100/121 = k^2

    If we square root both sides we get:

    10/11 = k or 0.909 recurring.

    • Jeff Aaron
      Lv 7
      1 year agoReport

      You forgot that k can also be -10/11

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  • 1 year ago

    Factor the left side as a difference of squares: 100 - 121k^2 = (10 + 11k)(10 - 11k). Then set each factor to 0 and continue.

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  • 1 year ago

    100 − 121k² = 0

    Add 112 k^2 to both sides of this equation.

    100 = 112 * k^2

    112 * k^2 = 100

    Divide both sides by 112.

    k^2 = 100 ÷ 112

    Let’s take the square root of both sides of this equation.

    k = ± (10 ÷ 11)

    This is approximately +0.909 or -0.909. I hope this is helpful for you.

    • ted s
      Lv 7
      1 year agoReport

      good thinking is ruined by poor math/typing....add 122 k²

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