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Best Answer:

Since the amount of mercury isn't given

we can assume any amount as long as it is enough that some

will be on each side of the U tube after the other components are added.

Since the mercury is the densest,

an amount equal to the glycerin will be more than sufficient.

Also just the lengths of the column can be used since in a

U tube of constant diameter the mass will vary directly with length.

----------------------

Assume the column with glycerin and mercury is 20 cm

(Note: any column height ≥ 10 will work -- try another number, You'll get the same answer!)

Then set the two sides equal

10 glycerin + 10 mercury = x oil + (20 - x)mercury

10 * 1300 + 10 * 13600 = x * 800 + (20 - x)13600

Expand

13000 + 136000 = 800x + 272000 - 13600x

Combine like terms

149000 = -12800x + 272000

Subtract 27200 from both sides

-123000 = -12800x

Divide both sides by -12800

x = 9.61 cm <–––––––

http://goo.gl/y49sTR

Since the amount of mercury isn't given

we can assume any amount as long as it is enough that some

will be on each side of the U tube after the other components are added.

Since the mercury is the densest,

an amount equal to the glycerin will be more than sufficient.

Also just the lengths of the column can be used since in a

U tube of constant diameter the mass will vary directly with length.

----------------------

Assume the column with glycerin and mercury is 20 cm

(Note: any column height ≥ 10 will work -- try another number, You'll get the same answer!)

Then set the two sides equal

10 glycerin + 10 mercury = x oil + (20 - x)mercury

10 * 1300 + 10 * 13600 = x * 800 + (20 - x)13600

Expand

13000 + 136000 = 800x + 272000 - 13600x

Combine like terms

149000 = -12800x + 272000

Subtract 27200 from both sides

-123000 = -12800x

Divide both sides by -12800

x = 9.61 cm <–––––––

http://goo.gl/y49sTR

Michael
· 1 year ago

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