The pollutant sulphur dioxide (SO2) can be removed from the air by the following reaction: 2CaCO3(s) + 2SO2(g) + O2(g) = 2CaSO4(s) + 2CO2(g)?

what mass of calcium carbonate is needed to remove 3kg of SO2?

(Ca=40 C=12 O=16 S=32)

I got, 3/RMM = 3/64 = 0.046875

0.046875 x RMM of calcium carbonate

0.046875 x 100 = 4.6875(g)

is this correct?
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