Use the "dilution equation".....

vol x conc of dilute soln = vol x conc of stock soln.

305 mL x 0.996M = ? mL x 4.19M

? = 72.5 mL

Have you given any thought has to how you are going to measure either 72.5 mL or 305 mL? Sure, you can calculate that you need 72.5 mL of the stock solution and then dilute it to 305 mL, but what will you dilute it in that you can measure 305 mL? There are no 305 mL volumetric flasks and using a 500 mL graduated cylinder to measure 305 mL is not very precise. Even measuring 72.5 mL of the stock solution is problematic.

Wouldn't it make more sense if the teacher gave a practical problem using numbers that actually match the glassware.

In the real world you wouldn't make 305 mL, nor would the base be diluted to 0.996M. In my lab we have 50mL, 100mL, 250mL, 500mL, 1000mL and 2000 mL volumetric flasks and 10mL, 25mL, 50mL and 100mL pipettes . Pick the glassware that is closest and compute the actual concentration that will be produced.

You might use the 100 mL pipette to make 500 mL of NaOH.

100 mL x 4.19M = 500 mL x ?M

? = 0.838M ............ will be the concentration of the NaOH