promotion image of download ymail app

Need help with this complex numbers problem.?

if |z1 + z2|>|z1-z2| then prove that -pi/2<arg(z1/z2)<pi/2 where z1 and z2 are complex numbers

1 Answer

  • Indica
    Lv 7
    3 years ago

    z₂=0 ⟹ |z₁| > |z₁| so z₂≠0. Hence can divide by z₂ to get |w+1| > |w−1| where w=z₁/z₂

    Squaring and using |u|²=uu’ where u’ is complex conjugate gives

    (w+1)(w’+1) > (w−1)(w’−1) which simplifies to w+w’ > 0 or Re(w) > 0

    ∴ w lies in either Q₁ or Q₄ and so it follows that -π/2 < arg(w) < π/2

    • Commenter avatarLog in to reply to the answers
Still have questions? Get answers by asking now.