A 10 percent salt solution is to be mixed with pure water to produce 55 gallons of a 3 percent salt solution? How much of each are needed?

Update:

I need to solve this problem with a system of equations. The equations that I had were x+y=55 and 0.10x+0.03y=55, which kept giving me a negative y value.

2 Answers

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  • Ian H
    Lv 7
    4 years ago

    The final mixture will be 55 gallons containing 3% salt, so that is equivalent to a pure salt content of 55* 3/100 = 33/20 = 1.65 gallons.

    That salt only comes from the 10% salt solution; it was 1/10th of 16.5 gallons

    So it was 16.5 gallons of the 10% solution and 38.5 gallons of water

    In terms of equations this is 0.1n = 0.03* 55

  • Your 2nd equation is wrong

    0.1 * x + 0 * y = 0.03 * 55

    You want 55 gallons of 3%. The water (y) is at 0%

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