What is the final temperature of 25 g of water at 22 degrees Celsius after it absorbs 454J of heat?

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  • 5 years ago
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    q = (mass) (temp change) (specific heat)

    454 J = (25 g) (x) (4.18 J/g C)

    x = 4.3444 C

    22 C + 4.3 C = 26.3 C

    The answer would be 26, based the fact that 22 does not have any decimal portion. see the rule on add/subtract with significant figures.

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