What is the final temperature of 25 g of water at 22 degrees Celsius after it absorbs 454J of heat?
- ChemTeamLv 75 years agoFavourite answer
q = (mass) (temp change) (specific heat)
454 J = (25 g) (x) (4.18 J/g C)
x = 4.3444 C
22 C + 4.3 C = 26.3 C
The answer would be 26, based the fact that 22 does not have any decimal portion. see the rule on add/subtract with significant figures.
Still have questions? Get answers by asking now.