Amber
Lv 6
Amber asked in Science & MathematicsChemistry · 6 years ago

Can someone answer this acid/base question?

Update:

A solution is prepared by adding 0.002 moles of sodium acetate to a 100 mL of 0.03 M acetic

acid.

(Ka (CH3COOH) = 1.8 x 10-5

)

a) Assuming that no volume change occurs upon addition of the sodium acetate what is the

pH of the solution?

1 Answer

Relevance
  • 6 years ago

    Sodium Acetate = CH3COONa

    Acetic Acid = CH3COOH

    In this case because sodium acetate is the limiting reactant, only 0.002 moles will of products will be produced. Aka only 0.002 moles of H+ will be produced.

    pH = 1/2 (pKa - log[H+])

    pH = 1/2 ( (-log(1.8x10^-5)) - (log[0.002]) )

    pH = 1/2 (7.443)

    pH = 3.72

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