Calorimetry Science homework help?
The students are recording their experiment to determine the heat of fusion when they add ice cubes to water. The final temp. is taken right after they have melted.
Mass of calorimeter (g) - 134.00
Mass of calorimeter and water (g) - 183.00
Mass of ice cubes (g) - 26.00
Initial temp. of water ( c) - 50.0
Final temp. of water ( c) - 7.5
a. Calculate the thermal energy lost by the calorimeter water.
b. Calculate the heat of fusion of the water
c. Calculate the percent error for this experiment
- FernLv 76 years agoFavourite answer
Mass of water = 183 – 134 = 49 g H2O
Energy lost by water = specific heat of water x temperature change x mass of water
a) Energy lost by water = 4.184 Joules/g C x (50 – 7.5) x 49 g H2O = 8713 Joules
b) 8713 Joules/ 26 g ice = 335 Joules/g
c) Value of heat of fusion from web = 333 Joules/g
Percent Error = difference between accepted value and experimental value/ accepted value * 100