C Programming counting program that counts from 1 to 100.?

Question

I need the steps for C Programming a counting program that counts from 1 to 100

Answer 1

int counter ( int count=1)

{

if ( count < 101 )

{

/*do something*/

return ( counter ( count+1 ) ) ;

}

else

return ( 0 ) ;

}

int main ()

{

return ( counter () ) ;

}

There you go counts from 1 to 100 recursively, of course you may want it to do something with the count variable like output to screen or else you've just wasted over 100 CPU cycles ;)

If you did want it to just count to 100 without displaying anything you could change counter to the following

int counter ( int count = 0 )

{

return ( ( count < 101 ? counter ( count+1 ) : 0 ) ) ;

}

}

Answer 2

i could attempt this: for (i=a million; i<a hundred;) { printf("%d ", i); i=i*2; } provides: a million 2 4 8 sixteen 32 sixty 4 (as a results of fact 128 > a hundred) Or are you desirous to maintain doubling a hundred circumstances? if so you desire an added variable: int j=a million; for (i=a million; i<a hundred;) { printf("%d ", j); j=j*2; i++; }

Answer 3

include<stdio.h>

int main()

{

int x=1; // Dont forget to declare variables

while (x<101){ //while x is less than 101

printf("%d\n",x);

x++; // update x so the condition can met eventually

}

getchar();

}

}