C Programming counting program that counts from 1 to 100.?

I need the steps for C Programming a counting program that counts from 1 to 100

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  • 8 years ago

    int counter ( int count=1)

    {

    if ( count < 101 )

    {

    /*do something*/

    return ( counter ( count+1 ) ) ;

    }

    else

    return ( 0 ) ;

    }

    int main ()

    {

    return ( counter () ) ;

    }

    There you go counts from 1 to 100 recursively, of course you may want it to do something with the count variable like output to screen or else you've just wasted over 100 CPU cycles ;)

    If you did want it to just count to 100 without displaying anything you could change counter to the following

    int counter ( int count = 0 )

    {

    return ( ( count < 101 ? counter ( count+1 ) : 0 ) ) ;

    }

    }

  • 4 years ago

    i could attempt this: for (i=a million; i<a hundred;) { printf("%d ", i); i=i*2; } provides: a million 2 4 8 sixteen 32 sixty 4 (as a results of fact 128 > a hundred) Or are you desirous to maintain doubling a hundred circumstances? if so you desire an added variable: int j=a million; for (i=a million; i<a hundred;) { printf("%d ", j); j=j*2; i++; }

  • 8 years ago

    include<stdio.h>

    int main()

    {

    int x=1; // Dont forget to declare variables

    while (x<101){ //while x is less than 101

    printf("%d\n",x);

    x++; // update x so the condition can met eventually

    }

    getchar();

    }

    }

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