# Prove 2n^n ≤ (n+1)^n...?

Using Bernoullis inequality

(1+a)^n ≥ 1+na for a>0

prove that 2n^n ≤ (n+1)^n.

Can anyone help please??

### 1 Answer

Relevance

- IndicaLv 78 years agoBest answer
Set a=1/n in (1+a)^n ≥ 1+na to get (1+1/n)^n ≥ 1+n(1/n) = 2

Multiply by n^n : (n+1)^n ≥ 2n^n

Still have questions? Get answers by asking now.