Prove 2n^n ≤ (n+1)^n...?
Using Bernoullis inequality
(1+a)^n ≥ 1+na for a>0
prove that 2n^n ≤ (n+1)^n.
Can anyone help please??
- IndicaLv 78 years agoBest answer
Set a=1/n in (1+a)^n ≥ 1+na to get (1+1/n)^n ≥ 1+n(1/n) = 2
Multiply by n^n : (n+1)^n ≥ 2n^n
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