# Got a math question I need help with?

1 1

___+ ___ =0

(x-2) (2x-1)

Solve for X. I dont know if I myself am over analyzing this problem but I am stuck. The one will not line up right when I submit, it is a one over both lines not 11.

Relevance
• 10 years ago

1/(x - 2) + 1/(2x - 1) = 0

2x - 1 + x - 2 = 0

3x = 3

x = 1

Proof:

1/(1 - 2) + 1/(2[1] - 1) = 0

1/(- 1) + 1/(2 - 1) = 0

- 1 + 1/(1) = 0

- 1 + 1 = 0

0 = 0

• 10 years ago

You can't add the two together yet because they do not have a common denominator, so multiply the numerators by (x-2)(2x-1).

THe denominators will cancel and you'll get 2x-1+x-2=0

Combine like terms: 3x-3=0

3x=3

x=1

• James
Lv 6
10 years ago

x = 1 (x not equal 2 ,1/2)

• 10 years ago

It's easy, just cross-multiply it

1/(x-2)+1/(2x-1)=0

Cross-multiply

(2x-1)+(x-2)=0

3x-3

3x=3

x=1

• 10 years ago

1/(X-2) = -1/(2x-1) so

x-2= 1-2x

3x = 3

x=1

• 10 years ago

1/(x - 2) + 1/(2x - 1) = 0

1/(x - 2) = -1/(2x - 1)

(x - 2)1/(x - 2) = (x - 2)(-1)/(2x - 1)

1 = (2 - x)/(2x - 1)

2x - 1 = 2 - x

3x = 3

x = 1

• w
Lv 6
10 years ago

1/(x-2)=-1/(2x-1)

-(2x-1)=x-2,

-2x+1=x-2,

3=3x,

x=1.

• 10 years ago

1/(2x-1)+1/(x-2)=0

x-2+2x-1/(x-2)(2x-1)=0

3x-3=0

3x=3

x=1