Got a math question I need help with?

1 1

___+ ___ =0

(x-2) (2x-1)

Solve for X. I dont know if I myself am over analyzing this problem but I am stuck. The one will not line up right when I submit, it is a one over both lines not 11.

8 Answers

Relevance
  • 10 years ago
    Favourite answer

    1/(x - 2) + 1/(2x - 1) = 0

    2x - 1 + x - 2 = 0

    3x = 3

    x = 1

    Answer: x = 1

    Proof:

    1/(1 - 2) + 1/(2[1] - 1) = 0

    1/(- 1) + 1/(2 - 1) = 0

    - 1 + 1/(1) = 0

    - 1 + 1 = 0

    0 = 0

  • 10 years ago

    You can't add the two together yet because they do not have a common denominator, so multiply the numerators by (x-2)(2x-1).

    THe denominators will cancel and you'll get 2x-1+x-2=0

    Combine like terms: 3x-3=0

    3x=3

    x=1

  • James
    Lv 6
    10 years ago

    x = 1 (x not equal 2 ,1/2)

  • 10 years ago

    It's easy, just cross-multiply it

    1/(x-2)+1/(2x-1)=0

    Cross-multiply

    (2x-1)+(x-2)=0

    3x-3

    3x=3

    x=1

  • What do you think of the answers? You can sign in to give your opinion on the answer.
  • 10 years ago

    1/(X-2) = -1/(2x-1) so

    x-2= 1-2x

    3x = 3

    x=1

  • 10 years ago

    1/(x - 2) + 1/(2x - 1) = 0

    1/(x - 2) = -1/(2x - 1)

    (x - 2)1/(x - 2) = (x - 2)(-1)/(2x - 1)

    1 = (2 - x)/(2x - 1)

    2x - 1 = 2 - x

    3x = 3

    x = 1

  • w
    Lv 6
    10 years ago

    1/(x-2)=-1/(2x-1)

    -(2x-1)=x-2,

    -2x+1=x-2,

    3=3x,

    x=1.

  • 10 years ago

    1/(2x-1)+1/(x-2)=0

    x-2+2x-1/(x-2)(2x-1)=0

    3x-3=0

    3x=3

    x=1

Still have questions? Get answers by asking now.