• Help me please to find T1 ineed answers:)?

    To practice Problem-Solving Strategy 11.1 Equilibrium of a Rigid Body. A horizontal uniform bar of mass 2.8 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to the end of the bar, and string 2 is attached a distance 0.7 m from the other end. A monkey of mass 1.4 kg walks from one end of the bar to the other.... show more
    To practice Problem-Solving Strategy 11.1 Equilibrium of a Rigid Body. A horizontal uniform bar of mass 2.8 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to the end of the bar, and string 2 is attached a distance 0.7 m from the other end. A monkey of mass 1.4 kg walks from one end of the bar to the other. Find the tension T1 in string 1 at the moment that the monkey is halfway between the ends of the bar. Find T1, the magnitude of the force of tension in string 1, at the moment that the monkey is halfway between the ends of the bar. Express your answer in newtons using three significant figures. T1 = ?
    1 answer · Physics · 1 month ago
  • Can u help me please physics :(?

    A nonuniform beam 4.65 m long and weighing 1.47 kN makes an angle of 25.0∘ below the horizontal. It is held in position by a frictionless pivot at its upper right end and by a cable 2.90 m farther down the beam and perpendicular to it in (Figure 1). The center of gravity of the beam is a distance of 1.90 m down the beam from the pivot. Lighting... show more
    A nonuniform beam 4.65 m long and weighing 1.47 kN makes an angle of 25.0∘ below the horizontal. It is held in position by a frictionless pivot at its upper right end and by a cable 2.90 m farther down the beam and perpendicular to it in (Figure 1). The center of gravity of the beam is a distance of 1.90 m down the beam from the pivot. Lighting equipment exerts a downward force of 4.90 kN on the end of the beam. Part D Find the y component of the force exerted on the beam by the pivot. Express your answer with the appropriate units. Enter positive value if the direction of the y component of the force is upward and negative value if the direction of the y component of the force is downward. https://session.masteringphysics.com/pro... Py =
    1 answer · Physics · 1 month ago
  • Help me :)?

    An object is undergoing simple harmonic motion with frequency f = 8.8 Hz and an amplitude of 0.13 m. At t = 0.00 s the object is at x = 0.00 m. How long does it take the object to go from x = 0.00 m to x = 6.00×10−2 m. An object is undergoing simple harmonic motion with frequency f = 8.8 Hz and an amplitude of 0.13 m. At t = 0.00 s the object is at... show more
    An object is undergoing simple harmonic motion with frequency f = 8.8 Hz and an amplitude of 0.13 m. At t = 0.00 s the object is at x = 0.00 m. How long does it take the object to go from x = 0.00 m to x = 6.00×10−2 m. An object is undergoing simple harmonic motion with frequency f = 8.8 Hz and an amplitude of 0.13 m. At t = 0.00 s the object is at x = 0.00 m. How long does it take the object to go from x = 0.00 m to x = 6.00×10−2 m. 5.45×10−2 seconds 8.68×10−3 seconds 5.81×10−3 seconds 1.97×10−2 seconds
    2 answers · Physics · 2 months ago
  • 4help me please?

    A vertical scale on a spring balance reads from 0 to 225 N . The scale has a length of 13.0 cm from the 0 to 225 N reading. A fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.10 Hz . Part A Ignoring the mass of the spring, what is the mass m of the fish? Express your answer in kilograms. m = kg
    A vertical scale on a spring balance reads from 0 to 225 N . The scale has a length of 13.0 cm from the 0 to 225 N reading. A fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.10 Hz . Part A Ignoring the mass of the spring, what is the mass m of the fish? Express your answer in kilograms. m = kg
    1 answer · Physics · 2 months ago
  • Help me in my exam please ineeed full solution :(?

    Two forces, of magnitudes F1 = 90.0 N and F2 = 45.0 N , act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1)Initially, the center of the block is at position xi = -6.00 cm . At some later time, the block has moved to the right, and its center is at a new position, xf = 5.00 cm . Part... show more
    Two forces, of magnitudes F1 = 90.0 N and F2 = 45.0 N , act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1)Initially, the center of the block is at position xi = -6.00 cm . At some later time, the block has moved to the right, and its center is at a new position, xf = 5.00 cm . Part A Find the work W1 done on the block by the force of magnitude F1 = 90.0 N as the block moves from xi = -6.00 cm to xf = 5.00 cm . Express your answer numerically, in joules. W1 = J Part B Find the work W2 done by the force of magnitude F2 = 45.0 N as the block moves from xi = -6.00 cm to xf = 5.00 cm . Express your answer numerically, in joules. W2 =J Part C What is the net work Wnet done on the block by the two forces? Express your answer numerically, in joules. Wnet = J Part D Determine the changeKf−Ki in the kinetic energy of the block as it moves from xi = -6.00 cm to xf = 5.00 cm . Express your answer numerically, in joules. Kf−Ki = J
    1 answer · Physics · 2 months ago
  • Help me with this please for my exam?

    A toy rocket is launched vertically from ground level (y = 0.00 m), at time t = 0.00 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 56 m and acquired a velocity of 60 m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls... show more
    A toy rocket is launched vertically from ground level (y = 0.00 m), at time t = 0.00 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 56 m and acquired a velocity of 60 m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground with negligible air resistance. The speed of the rocket upon impact on the ground is closest to A toy rocket is launched vertically from ground level (y = 0.00 m), at time t = 0.00 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 56 m and acquired a velocity of 60 m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground with negligible air resistance. The speed of the rocket upon impact on the ground is closest to 84 m/s 77 m/s 63 m/s 69 m/s 56 m/s
    2 answers · Physics · 2 months ago
  • HELP Me please exammss?

    A 0.24-kg block on a horizontal frictionless surface is attached to an ideal massless spring whose spring constant is 310 N/m. The block is pulled from its equilibrium position at x = 0.00 m to a displacement x = +0.080 m and is released from rest. The block then executes simple harmonic motion along the horizontal x-axis. When the displacement is x... show more
    A 0.24-kg block on a horizontal frictionless surface is attached to an ideal massless spring whose spring constant is 310 N/m. The block is pulled from its equilibrium position at x = 0.00 m to a displacement x = +0.080 m and is released from rest. The block then executes simple harmonic motion along the horizontal x-axis. When the displacement is x = 2.6×10−2 m, what is the kinetic energy of the block? A 0.24-kg block on a horizontal frictionless surface is attached to an ideal massless spring whose spring constant is 310 N/m. The block is pulled from its equilibrium position at x = 0.00 m to a displacement x = +0.080 m and is released from rest. The block then executes simple harmonic motion along the horizontal x-axis. When the displacement is x = 2.6×10−2 m, what is the kinetic energy of the block? 0.94 J 0.89 J 1.0 J 0.83 J 0.99 J
    1 answer · Physics · 2 months ago
  • Please hep me fast for my exam :)?

    If the fastest you can safely drive is 65 mi/h, what is the longest time you can stop for dinner if you must travel 488 mi in 9.8 h total? If the fastest you can safely drive is 65 mi/h, what is the longest time you can stop for dinner if you must travel 488 mi in 9.8 h total? 1.8 h 2.3 h 2.8 h You can't stop at all.
    If the fastest you can safely drive is 65 mi/h, what is the longest time you can stop for dinner if you must travel 488 mi in 9.8 h total? If the fastest you can safely drive is 65 mi/h, what is the longest time you can stop for dinner if you must travel 488 mi in 9.8 h total? 1.8 h 2.3 h 2.8 h You can't stop at all.
    1 answer · Physics · 2 months ago
  • Ineed fast help for my exam please?

    When a flea (m = 450 μg) is jumping up, it extends its legs 0.5 mm and reaches a speed of 0.40 m/s in that time. Part A How much work did the flea do during that time? Use g = 10 m/s2 How much work did the flea do during that time? Use = 10 3.8×10−2 mJ 3.8×10−5 mJ 3.6×10−5 mJ 2.3×10−6 mJ
    When a flea (m = 450 μg) is jumping up, it extends its legs 0.5 mm and reaches a speed of 0.40 m/s in that time. Part A How much work did the flea do during that time? Use g = 10 m/s2 How much work did the flea do during that time? Use = 10 3.8×10−2 mJ 3.8×10−5 mJ 3.6×10−5 mJ 2.3×10−6 mJ
    1 answer · Physics · 2 months ago
  • Help me please anyone know physics :(?

    The displacement of an oscillating object of mass, 10.0 kg , and total energy, −5.40×10−4 J , as a function of time is shown in the figure(Figure 1). help me please Part A What is the frequency? f = Hz Part B What is the amplitude? A = cm Part C What is the period? T = s Part D ... show more
    The displacement of an oscillating object of mass, 10.0 kg , and total energy, −5.40×10−4 J , as a function of time is shown in the figure(Figure 1). help me please Part A What is the frequency? f = Hz Part B What is the amplitude? A = cm Part C What is the period? T = s Part D What is the angular frequency of this motion? ω = rad/s Request Answer Part E What is the spring constant? k = N/m Part F What is the maximal speed? vmax = cm/s Part G What is the maximal force? Fmax = N Part H What is the minimal potential energy? Umin = J Part I What is the maximal power of the spring on the attached mass? pmax = Watt Part J What is the position of equilibrium? (¯x) = m Part K What is the speed when t=10 s ? v = cm/s
    1 answer · Physics · 2 months ago