• Would the area corresponding to the P-value be on the left, on the right, or on both sides of the mean?

    Best answer: (b) Ha: mu2 > mu1 (c) Ha: mu2 < mu1 (d) Ha: mu2 not equal to mu1 (e) right, left, both and I don't understand how (a) is different from the aggregate of questions b,c,d.
    Best answer: (b) Ha: mu2 > mu1 (c) Ha: mu2 < mu1 (d) Ha: mu2 not equal to mu1 (e) right, left, both and I don't understand how (a) is different from the aggregate of questions b,c,d.
    1 answer · Mathematics · 9 hours ago
  • I have a standard deck of 52 cards. How do I find the number of hands of 13 cards that contain 4 cards of the same rank? (A,2-10, J,Q,K)?

    The number of 13-card hands that contain four aces would be C(48,9) = 48!/(9! 39!) = 1,677,106,640. The number of 13-card hands that contain four kings would also be 1,677,106,640, but some of the 4-king hands were already counted, as they also contain 4 aces. The number of 13-card hands containing BOTH 4 aces AND 4 kings would be C(44,5) =... show more
    The number of 13-card hands that contain four aces would be C(48,9) = 48!/(9! 39!) = 1,677,106,640. The number of 13-card hands that contain four kings would also be 1,677,106,640, but some of the 4-king hands were already counted, as they also contain 4 aces. The number of 13-card hands containing BOTH 4 aces AND 4 kings would be C(44,5) = 1,086,008. The number of 13-card hands that contain 4 queens is 1,677,106,640, but 1,086,008 of those hands also contain four aces; and 1,086,008 of the 4-queen hands also contain four kings; on the other hand, there are 10 hands that contain 4 aces AND 4 kings AND 4 queens...and we don't want to subtract these hands more than once. So the answer to your question will be 13*1,677,106,640 - C(13,2)*1,086,008 + + C(13,3)*10 = 13*1,677,106,640 - 78*1,086,008 + 2860. Now use a calculator to simplify that last line!
    2 answers · Mathematics · 10 hours ago
  • Please help me with with trig identies?

    No, but 1/[cos^2(x)*sin^2(x)] can be written as sec^2(x)*cosec^2(x). Which is probably what you meant. What's really WRONG with what you typed is that the first expression in your question is typed in such a way that it means [1/cos^2(x)]*sin^2(x). Whenever you replace a horizontal fraction bar with a diagonal slash, you must add symbols of... show more
    No, but 1/[cos^2(x)*sin^2(x)] can be written as sec^2(x)*cosec^2(x). Which is probably what you meant. What's really WRONG with what you typed is that the first expression in your question is typed in such a way that it means [1/cos^2(x)]*sin^2(x). Whenever you replace a horizontal fraction bar with a diagonal slash, you must add symbols of inclusion (parens, brackets, braces) to show the numerator and denominator as they were intended.
    6 answers · Mathematics · 11 hours ago
  • Do you think time travel will ever be invented?

    Einstein and Hawking say no to the time travel. The flying cars should be possible, if anyone wants to pay for them.
    Einstein and Hawking say no to the time travel. The flying cars should be possible, if anyone wants to pay for them.
    17 answers · Polls & Surveys · 13 hours ago
  • Use Law of Sines to solve the triangle where B=35°,A=85°,and c=30. Round length to the nearest tenth and angle measure to the nearest degree?

    C = 180 - 120 = 60. A = C*sin(85)/sin(60), and B = C*sin(35)/sin(60). Now just use a calculator.
    C = 180 - 120 = 60. A = C*sin(85)/sin(60), and B = C*sin(35)/sin(60). Now just use a calculator.
    5 answers · Mathematics · 13 hours ago
  • Help with this math question!?

    sec(0) = 1/[cos(0)] = 1/1 = 1.
    sec(0) = 1/[cos(0)] = 1/1 = 1.
    4 answers · Mathematics · 14 hours ago
  • Use the Law Of Cosines to find angle B if c =1, b=4, and A=100°. Round to the nearest degree.?

    a^2 = 1 + 16 - 2*1*4*cos(100 deg) = 18.3892, and therefore a = 4.288 Once you have "a," then 16 = 18.3892 + 1 - 2*1*4.288*cos(B), and cos(B) = 3.3892/8.576; now use a calculator to find cos(B) and angle B.
    a^2 = 1 + 16 - 2*1*4*cos(100 deg) = 18.3892, and therefore a = 4.288 Once you have "a," then 16 = 18.3892 + 1 - 2*1*4.288*cos(B), and cos(B) = 3.3892/8.576; now use a calculator to find cos(B) and angle B.
    5 answers · Mathematics · 14 hours ago
  • Consider the function below. f(x) = 7sqr√x e^-x?

    f'(x) = 7e^(-x)/[2*sqrt(x)] - 7e^(-x)*sqrt(x). Note that f(0) = 0, and that f(x) will be near zero when x is very large; yet f(x) > 0 for all x>0. That's one way to know that there will BE a local maximum. The maximum occurs where f'(x) = 0, so where 7/[2*sqrt(x)] = 7*sqrt(x) => x = sqrt(2)/2. I expect the graph will be... show more
    f'(x) = 7e^(-x)/[2*sqrt(x)] - 7e^(-x)*sqrt(x). Note that f(0) = 0, and that f(x) will be near zero when x is very large; yet f(x) > 0 for all x>0. That's one way to know that there will BE a local maximum. The maximum occurs where f'(x) = 0, so where 7/[2*sqrt(x)] = 7*sqrt(x) => x = sqrt(2)/2. I expect the graph will be concave downward for all x to the left of an inflection, and concave upward for all x to the right of the inflection point. To find the inflection point, we need f"(x): -7e^(-x)/[2*sqrt(x)] - 7e^(-x)/[4*x^(3/2)] + 7e^(-x)*sqrt(x) - 7e^(-x)/[2*sqrt(x)] . This will be 0 where 7*sqrt(x) = 7/[sqrt(x)] + 7/[4x*sqrt(x)] => x = 1 + 1/(4x) => 4x^2 - 4x - 1 = 0 => x = (1/2) +/- (1/8)*sqrt(80) = (1/2) +/- (1/2)*sqrt(5). The negative answer doesn't "work" as the original function is not defined on the negative domain. Thus the only inflection point occurs around x = 1.6180339... (the "golden ratio" number!). The graph is concave downward for x < 1.618033 and concave upward for x > 1.618034.
    2 answers · Mathematics · 15 hours ago
  • Mean medían and fashion 5 stars?

    Best answer: A: sum = 47, so the mean is 4.7. The median is 4, as both of the middle numbers (of the ordered set) are 4. The mode is 2, and believe me, nobody in math calls it the "fashion." B: sum = 55, so the mean is 5.5. The median is 5 as both of the middle numbers of the ordered set are 5. There are three modes (9,5,2); it... show more
    Best answer: A: sum = 47, so the mean is 4.7. The median is 4, as both of the middle numbers (of the ordered set) are 4. The mode is 2, and believe me, nobody in math calls it the "fashion." B: sum = 55, so the mean is 5.5. The median is 5 as both of the middle numbers of the ordered set are 5. There are three modes (9,5,2); it doesn't make a lot of sense to think of the mode as a measure of central tendency in this case. C: sum = 83, so the mean is 83/13 = about 6.4. The median is the middle number of the ordered set, which is 8. The mode is obviously 8, there are a whole lot of them!
    1 answer · Mathematics · 19 hours ago
  • Need help in organic chemistry?

    Organic chem, are you kidding me? This is a question for junior high school, and the answer is steam at 110C.
    Organic chem, are you kidding me? This is a question for junior high school, and the answer is steam at 110C.
    2 answers · Chemistry · 20 hours ago
  • Can a Medicaid patient see a doctor in another state?

    Federal law requires that Medicaid patients who experience a medical emergency while traveling out of state be reimbursed or paid for by the state where they are enrolled in Medicaid. However, it's not always easy to make this happen. Google "Interstate Medicaid Billing Problems" to see a document that describes some of the problems. show more
    Federal law requires that Medicaid patients who experience a medical emergency while traveling out of state be reimbursed or paid for by the state where they are enrolled in Medicaid. However, it's not always easy to make this happen. Google "Interstate Medicaid Billing Problems" to see a document that describes some of the problems.
    2 answers · Medicine · 21 hours ago
  • Are there far more hotter places than colder places on the planet earth since low latitude areas occupy more areas than high latitude area?

    You are right in pointing out that the areas with low latitudes are larger than the areas with high latitudes. But then the question is, hotter than what? It is very possible to have freezing temperatures at latitudes as low as 30 degrees from time to time; and half of the planet has latitudes higher than 30 degrees.
    You are right in pointing out that the areas with low latitudes are larger than the areas with high latitudes. But then the question is, hotter than what? It is very possible to have freezing temperatures at latitudes as low as 30 degrees from time to time; and half of the planet has latitudes higher than 30 degrees.
    3 answers · Astronomy & Space · 21 hours ago
  • Suppose x and y are differentiable functions of t and suppose that when t = 22, dx/dt= 6, dy/dt= 2, x = 150 and y = 80.?

    2s ds/dt = 2x dx/dt + 2y dy/dt. When t = 22, you have s = +/-170, so ds/dt = [1800 + 320]/(+/-170) = use calculator, there are just two answers.
    2s ds/dt = 2x dx/dt + 2y dy/dt. When t = 22, you have s = +/-170, so ds/dt = [1800 + 320]/(+/-170) = use calculator, there are just two answers.
    1 answer · Mathematics · 21 hours ago
  • Ps113 help?

    One billionth of the 10^34 J from the table would be 10^25 J. So I guess the answer they want is 10^25/(4 x 10^20) = 2.5 x 10^4, i.e., 25000 years.
    One billionth of the 10^34 J from the table would be 10^25 J. So I guess the answer they want is 10^25/(4 x 10^20) = 2.5 x 10^4, i.e., 25000 years.
    1 answer · Physics · 22 hours ago
  • (4 x 10^-5) + (2 x 10^-5) / (3 x 10^7)?

    If you meant what you wrote, the answer is very close to 0.00004. Because what you wrote means (4 x 10^(-5)) + [(2 x 10^(-5))/(3 x 10^(7)], and the second term is 10 million times smaller than the first term. If you instead meant [(4 x 10^(-5)) + (2 x 10^(-5))] / (3 x 10^7), the answer is 2 x 10^(-12).
    If you meant what you wrote, the answer is very close to 0.00004. Because what you wrote means (4 x 10^(-5)) + [(2 x 10^(-5))/(3 x 10^(7)], and the second term is 10 million times smaller than the first term. If you instead meant [(4 x 10^(-5)) + (2 x 10^(-5))] / (3 x 10^7), the answer is 2 x 10^(-12).
    3 answers · Mathematics · 22 hours ago
  • How would aliens know how to convert binary into decimal, let alone how to read binary?

    We can't expect them to read English. Unless they have 10 fingers, it's not too likely that they'd be accustomed to a decimal system. Binary might not be intelligible, but it's more likely to be understood than any other scheme.
    We can't expect them to read English. Unless they have 10 fingers, it's not too likely that they'd be accustomed to a decimal system. Binary might not be intelligible, but it's more likely to be understood than any other scheme.
    8 answers · Astronomy & Space · 22 hours ago
  • Find derivative of t^(7/6)log(base 3)(t+3)^(1/2)?

    I guess that's log(base 3) of [(t+3)^(1/2)], rather than [log(base 3) of (t+3)]^(1/2). Anyway, log(base 3) of [(t+3)^(1/2)] is the same as (1/2)*log(base 3) of (t+3). Derivative of your function is (7/6)t^(1/6)*(1/2)*log(base 3)(t+3) + (1/2)t^(7/6)/[(t+3)ln(3)]. What direction to go with simplification depends on what you want to use the... show more
    I guess that's log(base 3) of [(t+3)^(1/2)], rather than [log(base 3) of (t+3)]^(1/2). Anyway, log(base 3) of [(t+3)^(1/2)] is the same as (1/2)*log(base 3) of (t+3). Derivative of your function is (7/6)t^(1/6)*(1/2)*log(base 3)(t+3) + (1/2)t^(7/6)/[(t+3)ln(3)]. What direction to go with simplification depends on what you want to use the derivative for...
    3 answers · Mathematics · 1 day ago
  • Whats the greatest common factor of 54 and 72?

    18, and you really should learn the times tables now, if you didn't learn them in third grade
    18, and you really should learn the times tables now, if you didn't learn them in third grade
    12 answers · Mathematics · 1 day ago
  • Problem Solving with Inequalities. Please help?

    If E = 120 and I < 12, then R > 10 ohms.
    If E = 120 and I < 12, then R > 10 ohms.
    4 answers · Engineering · 1 day ago
  • How do I solve this Calculus based physics problem on a fighter jet?

    Your teacher is a moron. The question is ambiguous at best, meaningless at worst.
    Your teacher is a moron. The question is ambiguous at best, meaningless at worst.
    1 answer · Physics · 1 day ago