• Logarithm help! ln(x+1)^2 = 1.5-ln(x-2)+ln(x+1)?

    ln(x+1)^2 = ln[ (e^1.5)(x+1)/(x-2) ] => (x+1)^2 = (e^1.5)(x+1)/(x-2) => x + 1 = (e^1.5)/(x - 2) => x^2 - x - 2 = e^1.5 = about 4.4817 => x^2 - x - 6.4817 = 0 => x = 1/2 +/- (1/2)*sqrt(1 + 25.9268) = 1/2 +/- (1/2)*5.18910. Only the "plus" will work in the original equation, as ln of a negative number does not exist. So you... show more
    ln(x+1)^2 = ln[ (e^1.5)(x+1)/(x-2) ] => (x+1)^2 = (e^1.5)(x+1)/(x-2) => x + 1 = (e^1.5)/(x - 2) => x^2 - x - 2 = e^1.5 = about 4.4817 => x^2 - x - 6.4817 = 0 => x = 1/2 +/- (1/2)*sqrt(1 + 25.9268) = 1/2 +/- (1/2)*5.18910. Only the "plus" will work in the original equation, as ln of a negative number does not exist. So you have x = 3.09455...
    2 answers · Mathematics · 28 mins ago
  • Math problem Help please?

    X^2 means the same thing as 1 times X^2. Definitely NOT zero times X^2. In your problem, A = 1, B = -6, C = -3.
    X^2 means the same thing as 1 times X^2. Definitely NOT zero times X^2. In your problem, A = 1, B = -6, C = -3.
    3 answers · Mathematics · 35 mins ago
  • I've been stressing over these math problems forever it seems, a little help would be appreciated?

    The length of PI is sqrt[(-6 - (-2))^2 + (-1/2 - (-4))^2] = sqrt(16 + 12.25) = use calculator. The length of EP is sqrt[(0 - (-2))^2 + (4 - (-4))^2] = sqrt(4 + 64) = use calculator. The length of IE is sqrt[(0 - (-6))^2 + (4 - (-1/2))^2] = sqrt(36 + 20.25) = use calculator. The second problem would be done using the same method as above. show more
    The length of PI is sqrt[(-6 - (-2))^2 + (-1/2 - (-4))^2] = sqrt(16 + 12.25) = use calculator. The length of EP is sqrt[(0 - (-2))^2 + (4 - (-4))^2] = sqrt(4 + 64) = use calculator. The length of IE is sqrt[(0 - (-6))^2 + (4 - (-1/2))^2] = sqrt(36 + 20.25) = use calculator. The second problem would be done using the same method as above.
    2 answers · Mathematics · 36 mins ago
  • What are some social media statistics?

    Google "number of facebook users history". As of the 3rd quarter of 2018, Facebook had 2.27 billion users who use it at least once a month.
    Google "number of facebook users history". As of the 3rd quarter of 2018, Facebook had 2.27 billion users who use it at least once a month.
    1 answer · Mathematics · 44 mins ago
  • Make the greatest possible six digit number by using the digits 6,5,7,0,2,3?

    If you are allowed to repeat, the answer is 777,777. If you are not allowed to repeat, the answer is 765,320.
    If you are allowed to repeat, the answer is 777,777. If you are not allowed to repeat, the answer is 765,320.
    10 answers · Mathematics · 1 hour ago
  • Height in Centimetres (Rounded to the nearest CM without a decimal point)?

    Are you kidding?
    Are you kidding?
    8 answers · Mathematics · 1 day ago
  • C2H4 +[O] +H2O=C2H6O2 34.5 kg of ethane were converted into 57.6 kg of ethane 1,2 diol Calculate the percentage yield?

    Molar mass of ethane is 24 + 4.06 = 28.06. Molar mass of C2H6O2 is 24 + 6.09 + 32 = 62.09. (34.5 kg)*(62.09/28.06) = 76.34; finally, 57.6/76.34 = 75.5%.
    Molar mass of ethane is 24 + 4.06 = 28.06. Molar mass of C2H6O2 is 24 + 6.09 + 32 = 62.09. (34.5 kg)*(62.09/28.06) = 76.34; finally, 57.6/76.34 = 75.5%.
    1 answer · Chemistry · 1 day ago
  • Modeling Multistage Modules ferrotec | Ferrotec-Nord.com?

    not a math question
    not a math question
    3 answers · Mathematics · 1 day ago
  • Does ammonium react with oxygen ?

    "Ammonium" is a radical (NH4). Maybe you meant "ammonia." ?? Ammonium oxide and ammonium hydroxide both exist, and their properties are extensively discussed in a 1953 paper by Hildenbrand and Giauque which is easy to find on the Internet. Ammonia (NH3) can be burned in air if the mixture proportions are just right. show more
    "Ammonium" is a radical (NH4). Maybe you meant "ammonia." ?? Ammonium oxide and ammonium hydroxide both exist, and their properties are extensively discussed in a 1953 paper by Hildenbrand and Giauque which is easy to find on the Internet. Ammonia (NH3) can be burned in air if the mixture proportions are just right.
    2 answers · Chemistry · 1 day ago
  • Chem help, stoichiometry!!?

    Ca(OH)2 + CO2 --> H2O + CaCO3. The molar mass of CO2 is 12 + 32 = 44.0. The molar mass of H2O is 18.015. So the answer is (5.9 tons)*(18.015/44.0) = about 2.4 tons of water, or 4800 pounds of water or 2177.24 kg of water. At 20C, the density of water is 998.2 kg/m^3, so the volume would be 2.18 m^3, about 2180 liters of water. show more
    Ca(OH)2 + CO2 --> H2O + CaCO3. The molar mass of CO2 is 12 + 32 = 44.0. The molar mass of H2O is 18.015. So the answer is (5.9 tons)*(18.015/44.0) = about 2.4 tons of water, or 4800 pounds of water or 2177.24 kg of water. At 20C, the density of water is 998.2 kg/m^3, so the volume would be 2.18 m^3, about 2180 liters of water.
    2 answers · Chemistry · 1 day ago
  • Find the centroid of the region lying underneath the graph of the function over the given interval.?

    As a reality check on Captain Matticus's answer, I'll calculate the numerical values of his answer. When I EYEBALL the graph of (1 + x^2)^(-1/2) on [0,8], it looks like the centroid should be x-bar = 2 or 3 and y-bar = 1/4 or 1/3. The values of CM's answers are x-bar = 2.544 and y-bar = 0.2605. Yup, that makes perfect sense !!! show more
    As a reality check on Captain Matticus's answer, I'll calculate the numerical values of his answer. When I EYEBALL the graph of (1 + x^2)^(-1/2) on [0,8], it looks like the centroid should be x-bar = 2 or 3 and y-bar = 1/4 or 1/3. The values of CM's answers are x-bar = 2.544 and y-bar = 0.2605. Yup, that makes perfect sense !!!
    2 answers · Mathematics · 1 day ago
  • Determine the mass of copper that has the same number of atoms as there are in 9.39 mg of potassium?

    Atomic masses: potassium 39.10, copper 63.55; so the answer is (9.39 mg)(63.55/39.10) = about 15 mg but use a calculator.
    Atomic masses: potassium 39.10, copper 63.55; so the answer is (9.39 mg)(63.55/39.10) = about 15 mg but use a calculator.
    1 answer · Chemistry · 2 days ago
  • How do I find centripetal acceleration with only the mass and radius?

    The centripetal force is the product of the mass and the centripetal acceleration. (Good old F = ma.)
    The centripetal force is the product of the mass and the centripetal acceleration. (Good old F = ma.)
    3 answers · Physics · 2 days ago
  • Can u tell me what is 7/9 divided by 1/6 or 7/9 * 6/1?

    42/9 = 14/3, or 4 2/3.
    42/9 = 14/3, or 4 2/3.
    5 answers · Mathematics · 2 days ago
  • Do ASL Interpreters get paid hourly?

    Working conditions and pay are set by contracts with particular employers, not by occupation. It seems unlikely, though, that the person would be given the full pay for the third hour.
    Working conditions and pay are set by contracts with particular employers, not by occupation. It seems unlikely, though, that the person would be given the full pay for the third hour.
    2 answers · Mathematics · 2 days ago
  • An 88 kg skydiver jumps out of an airplane at an altitude of 1198 m and opens the parachute at an altitude of 132 m.?

    Gravitational force is (9.8 m/s^2)(88 kg) = 862.4 N. Let's take the given retarding forces at face value, even though the notion that the force with the parachute open would exceed the gravitational force could not possibly be true if the diver were not already moving downward very fast. In the first 1066 meters of falling, the diver's... show more
    Gravitational force is (9.8 m/s^2)(88 kg) = 862.4 N. Let's take the given retarding forces at face value, even though the notion that the force with the parachute open would exceed the gravitational force could not possibly be true if the diver were not already moving downward very fast. In the first 1066 meters of falling, the diver's downward acceleration is 9.8 m/s^2 - 49N/(88 kg) = 9.2432 m/s^2, so his speed when he opens the parachute is sqrt(2*a*d) = sqrt(2*1066*9.2432) = 140.38 m/s. After opening the parachute, the diver accelerates upward by (3426 N)/(88 kg) - 9.8 m/s^2 = 29.132 m/s^2. So his speed when he hits the ground is found from 2*29.132*132 = 140.38^2 - vf^2 => vf = sqrt(12015.7) = 109.6 m/s (downward).
    2 answers · Physics · 2 days ago
  • What value of θ will maximize the trough's volume?

    The height of the trough is 9*cos(theta). The horizontal leg of each small triangle is 9*sin(theta). The area of the rectangle is 36*cos(theta). The area of the two small triangles together is 81*sin(theta)*cos(theta) or 40.5*sin(2*theta). The total cross-sectional area of the trough is A = 36*cos(theta) + 40.5*sin(2*theta). dA/d(theta) =... show more
    The height of the trough is 9*cos(theta). The horizontal leg of each small triangle is 9*sin(theta). The area of the rectangle is 36*cos(theta). The area of the two small triangles together is 81*sin(theta)*cos(theta) or 40.5*sin(2*theta). The total cross-sectional area of the trough is A = 36*cos(theta) + 40.5*sin(2*theta). dA/d(theta) = -36*sin(theta) + 81*cos(2*theta). Setting this expression to 0, we get 36*sin(theta) = 81*cos(2*theta) => 4*sin(theta) = 9*[cos^2(theta) - sin^2(theta)] => 4*sin(theta) = 9*[1 - 2*sin^2(theta)] => 18*sin^2(theta) + 4*sin(theta) - 9 = 0. Using the quadratic formula, you have sin(theta) = -1/9 +/- (1/36)*sqrt(16+648) = +0.60467. theta = 37.2 degrees. To see that this makes SOME sense, note that if theta = 45 degrees, the cross-section area is 81/2 + 18*sqrt(2) = about 66; if theta = 30 degrees, the cross-section area is 81*sqrt(3)/4 + 18*sqrt(3) = about 66.25; but if theta = 36.87 degrees (giving 3-4-5 triangles), the area is 972/25 + 3.2*9 = around 67.68...i.e., a little bigger than what you get for theta = 30 or 45.
    3 answers · Mathematics · 2 days ago
  • What are the zeros of the equation -3x^4+27x^2+1200=0?

    Let u = x^2, you have -3u^2 + 27u + 1200 = 0 => u^2 - 9u - 400 = 0 => (u - 25)(u + 16) = 0 => u = 25 or -16, so x is either +/-5 or +/-4i. Probably they want the "real" zeros, so that would be the +/- 5.
    Let u = x^2, you have -3u^2 + 27u + 1200 = 0 => u^2 - 9u - 400 = 0 => (u - 25)(u + 16) = 0 => u = 25 or -16, so x is either +/-5 or +/-4i. Probably they want the "real" zeros, so that would be the +/- 5.
    4 answers · Mathematics · 2 days ago
  • Are we alone in the universe? And do you think they might’ve visited Earth? Why? Or why not?

    Not alone in the universe. The probability that any extraterrestrial species has visited the earth is very close to zero, but we can never know for sure.
    Not alone in the universe. The probability that any extraterrestrial species has visited the earth is very close to zero, but we can never know for sure.
    11 answers · Astronomy & Space · 2 days ago