• Sketch shows graph of y=f(x). Write coordinates of points for the graph of... How would I move the graph depending on the function?

    y = -f(x) flips the graph vertically. y = f(-x) flips the graph horizontally across the y axis. y = f(x) + 2 raises the graph 2 units vertically. y = f(3x) shrinks the graph horizontally by a factor of 3. y = f(x/4) stretches the graph horizontally by a factor of 4. y = 5f(x) stretches the graph vertically by a factor of 5.
    y = -f(x) flips the graph vertically. y = f(-x) flips the graph horizontally across the y axis. y = f(x) + 2 raises the graph 2 units vertically. y = f(3x) shrinks the graph horizontally by a factor of 3. y = f(x/4) stretches the graph horizontally by a factor of 4. y = 5f(x) stretches the graph vertically by a factor of 5.
    1 answer · Mathematics · 19 mins ago
  • Can 3x^2 - x + 2 be factored?

    Clearly not, as (-1)^2 - 4*3*2 is less than 0.
    Clearly not, as (-1)^2 - 4*3*2 is less than 0.
    6 answers · Mathematics · 23 mins ago
  • Factor by Grouping 3x^2-4xy+3x-4y steps? I am trying to learn from examples, I don't want the answer per say only the steps.?

    When you just look at it, the pattern suggests x(3x - 4y) + 1(3x - 4y). So the factorization is of course (x+1)(3x - 4y).
    When you just look at it, the pattern suggests x(3x - 4y) + 1(3x - 4y). So the factorization is of course (x+1)(3x - 4y).
    5 answers · Mathematics · 59 mins ago
  • F '(4) = 24(2)^1/2 + C. and f'(4) = 17 and i'm trying to isolate for C?

    f"(t) = 12/sqrt(t) => f'(t) = 24*sqrt(t) + C, we agree so far. If f'(4) = 17, then 24*sqrt(4) + C = 17, so 48 + C = 17, and C = -31.
    f"(t) = 12/sqrt(t) => f'(t) = 24*sqrt(t) + C, we agree so far. If f'(4) = 17, then 24*sqrt(4) + C = 17, so 48 + C = 17, and C = -31.
    2 answers · Mathematics · 2 hours ago
  • The function f is continuous on the interval [3, 13] with selected values of x and f(x) given in the table below...?

    The answer given by Anonymous (5) makes more sense than the answer given by RealPro (2.75). Evidently the slope increases rapidly, somewhere in the interval between x = 7 and x = 13.
    The answer given by Anonymous (5) makes more sense than the answer given by RealPro (2.75). Evidently the slope increases rapidly, somewhere in the interval between x = 7 and x = 13.
    3 answers · Mathematics · 2 hours ago
  • F ''(t) = 7et + 5 sin(t), f(0) = 0, f(π) = 0?

    If you meant F"(t) = 7e^t + 5 sin(t), then F'(t) = 7e^t - 5 cos(t) + C1, and F(t) = 7e^t - 5 sin(t) + C1 t + C2. Therefore, f(0) = 0 = 7e^0 + C2 => C2 = -7; and f(pi) = 0 = 7e^pi + C1*pi - 7 => C1 = 7(1 - e^pi)/pi
    If you meant F"(t) = 7e^t + 5 sin(t), then F'(t) = 7e^t - 5 cos(t) + C1, and F(t) = 7e^t - 5 sin(t) + C1 t + C2. Therefore, f(0) = 0 = 7e^0 + C2 => C2 = -7; and f(pi) = 0 = 7e^pi + C1*pi - 7 => C1 = 7(1 - e^pi)/pi
    3 answers · Mathematics · 3 hours ago
  • Algebra and functions help - graphs and transformations?

    Because 3/x^2 is always positive, we will consider only the positive domain. If 4/x > 3/x^2, then 4/3 > x/x^2 = 1/x, so x > 3/4. Check: Note that 4/1 > 3/1 and 4/2 > 3/4, and 4/4 > 3/16, while 4/(1/2) is NOT greater than 3/(1/4), because the former is 8 and the latter is 12. Answer: (3/4,+infinity) open interval show more
    Because 3/x^2 is always positive, we will consider only the positive domain. If 4/x > 3/x^2, then 4/3 > x/x^2 = 1/x, so x > 3/4. Check: Note that 4/1 > 3/1 and 4/2 > 3/4, and 4/4 > 3/16, while 4/(1/2) is NOT greater than 3/(1/4), because the former is 8 and the latter is 12. Answer: (3/4,+infinity) open interval
    2 answers · Mathematics · 3 hours ago
  • Solve 2x+6 over 4x-8?

    Nothing to "solve." The ratio could be expressed as (x+3)/(2x - 4), or as (1/2) + 5/(2x - 4).
    Nothing to "solve." The ratio could be expressed as (x+3)/(2x - 4), or as (1/2) + 5/(2x - 4).
    5 answers · Mathematics · 4 hours ago
  • A computer is printing out subsets of a 6 element set?

    (a) I agree, 129. (b) Each of the 64 subsets could be printed 4 times, but there would be at least a 5th instance of at least one of them. Answer = 5.
    (a) I agree, 129. (b) Each of the 64 subsets could be printed 4 times, but there would be at least a 5th instance of at least one of them. Answer = 5.
    1 answer · Mathematics · 4 hours ago
  • Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.)?

    y = x^(1/3) => dy = (1/3)x^(-2/3) dx. In your problem, dx is 1, x is 27, so dy = (1/3)(1/9)(1) = 1/27, and the cube root of 28 is around 3 + 1/27 = 3.037... Calculator says the cube root of 28 is 3.03659, more or less.
    y = x^(1/3) => dy = (1/3)x^(-2/3) dx. In your problem, dx is 1, x is 27, so dy = (1/3)(1/9)(1) = 1/27, and the cube root of 28 is around 3 + 1/27 = 3.037... Calculator says the cube root of 28 is 3.03659, more or less.
    1 answer · Mathematics · 4 hours ago
  • Need help in math. Im solving for the general equations. I need to know how to do #14, 15, and 16. Im completley lost.?

    Very poor photograph. Please type out the equations you are trying to solve.
    Very poor photograph. Please type out the equations you are trying to solve.
    2 answers · Mathematics · 4 hours ago
  • Struggling with the concept of snapshot vs history graphs. Would really appreciate help on how to find solution for this question. Thank you?

    Best answer: From the history graph you can see that it takes 3 seconds to make two full cycles, so the frequency is 1.5 Hz. From the snapshot graph, it appears the wavelength is 1.5 cm. So the speed is (1.5 cm)(1.5 / s) = 1 cm/s. It's going right to left, and that's where I get "plus" in the equation below. y = (2... show more
    Best answer: From the history graph you can see that it takes 3 seconds to make two full cycles, so the frequency is 1.5 Hz. From the snapshot graph, it appears the wavelength is 1.5 cm. So the speed is (1.5 cm)(1.5 / s) = 1 cm/s. It's going right to left, and that's where I get "plus" in the equation below. y = (2 cm)*sin(2*pi/lambda)*(x + nu*t) = (2 cm)*sin{(6.2832/1.5 cm)*[x + (1.5/s)*t]} = (2 cm)*sin{[4.189 cm^(-1)]*[x + (1.5/s)*t]}
    1 answer · Physics · 5 hours ago
  • Physics homework question!?

    Angular momentum is I*(omega). #5. I = (mass of earth)*(square of earth-sun distance) and omega = (2*pi)/(1 year) = 1.99 x 10^(-7) per second. Use a calculator, answer comes out in kg m^2/s. #6. The law says that in the absence of external torque, angular momentum is conserved. When a skater pulls in his or her arms, the "I" (moment... show more
    Angular momentum is I*(omega). #5. I = (mass of earth)*(square of earth-sun distance) and omega = (2*pi)/(1 year) = 1.99 x 10^(-7) per second. Use a calculator, answer comes out in kg m^2/s. #6. The law says that in the absence of external torque, angular momentum is conserved. When a skater pulls in his or her arms, the "I" (moment of inertia) is reduced, so the "omega" (rotation rate) must increase.
    2 answers · Physics · 5 hours ago
  • I m in engineering school after I paused my studies for years.How to finish the degree fast?Study all day?

    You don't say why you want to "finish the degree fast." If the motivation is financial, you might be better off taking another pause in the middle, while you (a) work at a related job and (b) study in your free time, now that you know what must be studied.
    You don't say why you want to "finish the degree fast." If the motivation is financial, you might be better off taking another pause in the middle, while you (a) work at a related job and (b) study in your free time, now that you know what must be studied.
    2 answers · Engineering · 5 hours ago
  • Do improper integrals always converge to a number?

    No, they usually don't. (If it's fair to compare one infinite set to another.) SOME improper integrals converge to a number; for instance the integral from x = 0 to infinity of e^(-x) dx is finite; but the integral from x = 1 to infinity of (1/x) dx is not.
    No, they usually don't. (If it's fair to compare one infinite set to another.) SOME improper integrals converge to a number; for instance the integral from x = 0 to infinity of e^(-x) dx is finite; but the integral from x = 1 to infinity of (1/x) dx is not.
    3 answers · Mathematics · 8 hours ago
  • Please solve this. a^2(c)√75a^5b^2c^3?

    I think you mean "simplify." There is nothing to "solve." Also, you have not indicated the extent of the radical, so I will assume it applies only to the 75. a^2*a^5 = a^7; c*c^3 = c^4; sqrt(75) = 5*sqrt(3); so the simplest way to write the result is 5a^7b^2c^4*sqrt(3).
    I think you mean "simplify." There is nothing to "solve." Also, you have not indicated the extent of the radical, so I will assume it applies only to the 75. a^2*a^5 = a^7; c*c^3 = c^4; sqrt(75) = 5*sqrt(3); so the simplest way to write the result is 5a^7b^2c^4*sqrt(3).
    4 answers · Mathematics · 8 hours ago
  • What means Passwords must have at least one non letter or digit character?

    Their phrasing is ambiguous, but it probably means you must include one or more characters that are neither letters or digits, such as $, %, @, <, !, or ]. No good password: John1986 Good password: Joh$n19!6
    Their phrasing is ambiguous, but it probably means you must include one or more characters that are neither letters or digits, such as $, %, @, <, !, or ]. No good password: John1986 Good password: Joh$n19!6
    6 answers · Mathematics · 9 hours ago
  • If humans had to one day leave earth due to, like, too much pollution or whatever, what other planets are habitable enough to move to?

    Serious scientists have studied the question of making Mars habitable. The proposition of McKay, Toon, & Kasting (Nature, 1991) calls for manufacturing CFCs on Mars at a rate that is probably not feasible. The proposition of Gerstell, Francisco, Yung et al. (PNAS, 2001) improves on this, providing a way to sustain a warm atmosphere with a... show more
    Serious scientists have studied the question of making Mars habitable. The proposition of McKay, Toon, & Kasting (Nature, 1991) calls for manufacturing CFCs on Mars at a rate that is probably not feasible. The proposition of Gerstell, Francisco, Yung et al. (PNAS, 2001) improves on this, providing a way to sustain a warm atmosphere with a plausible amount of fluorocarbon manufacture; but does not address the question of how to initiate a warm atmosphere on Mars. See later references to the work of Chris McKay with Margarita Marinova for further suggestions about terraforming. A 2017 article by Roberto Candanosa, published by the American Chemical Society, discusses the feasibility of growing green plants on Mars. All of these, put together, do not yet constitute a plan for living on Mars, but that is the question on which many disparate efforts are trying to converge.
    17 answers · Astronomy & Space · 15 hours ago
  • A long wire carrying 100 A is perpendicular to the magnetic field lines of a uniform magnetic field of magnitude 5.0 mT.?

    We seek a point where the field due to the current is exactly 5 mT. The field due to the current is B = (mu-nought)*I/(2*pi*r) => (5.0 mT) = (4*pi*10^(-7) N/A^2)*(100 A)/(2*pi*r) => r = (4*pi*10^(-7))*100 m/(2*pi*0.005) = 0.025 m, or 2.5 cm.
    We seek a point where the field due to the current is exactly 5 mT. The field due to the current is B = (mu-nought)*I/(2*pi*r) => (5.0 mT) = (4*pi*10^(-7) N/A^2)*(100 A)/(2*pi*r) => r = (4*pi*10^(-7))*100 m/(2*pi*0.005) = 0.025 m, or 2.5 cm.
    1 answer · Physics · 15 hours ago
  • A racquet ball with mass m = 0.238 kg is moving toward the ........?

    Best answer: (a) magnitude of the initial momentum is (0.238 kg)(12.5 m/s) = 2.975 kg*m/s. (b) The horizontal component of the initial momentum is (0.238 kg)(12.5 m/s)*cos(31) = 2.550 kg*m/s. The change in momentum is -2*2.550 kg*m/s, so the magnitude of the change is 5.10 kg*m/s. (c) average F = delta-p/delta-t = (5.10 kg*m/s)/(0.078 s) = 65.4... show more
    Best answer: (a) magnitude of the initial momentum is (0.238 kg)(12.5 m/s) = 2.975 kg*m/s. (b) The horizontal component of the initial momentum is (0.238 kg)(12.5 m/s)*cos(31) = 2.550 kg*m/s. The change in momentum is -2*2.550 kg*m/s, so the magnitude of the change is 5.10 kg*m/s. (c) average F = delta-p/delta-t = (5.10 kg*m/s)/(0.078 s) = 65.4 N. (d) |delta-p| = (20.4 m/s)*(0.238 kg) = 4.855 kg*m/s. (e) t = (4.855 kg*m/s)/(65.4 N) = 0.0742 s. (f) Change in KE is (1/2)(0.238 kg)[(7.9 m/s)^2 - (12.5 m/s)^2] = about -10 J but use a calculator.
    1 answer · Physics · 15 hours ago